00:00 | this is a topic resuming after the . Um I would say that this |
|
00:07 | a topic attenuation and its connection with , which is not very intuitive. |
|
00:15 | so I would even say that probably lot of practicing show physicists don't understand |
|
00:20 | , but you will. So let go into presentation mode here and consider |
|
00:29 | following. Consider the following simple You have an impulsive source at the |
|
00:35 | in an ungrounded medium, no surface without attenuation and dispersion. So you |
|
00:42 | decompose this uh fourier source like So it's an impulsive source. So |
|
00:50 | is equal to one at T. zero and zero everywhere else. And |
|
00:57 | the uh that time series can be into this um uh spectrum and the |
|
01:10 | spectrum delta omega. This is delta . That fourier spectrum is flat, |
|
01:17 | equal to one everywhere, positive one , no imaginary part. And so |
|
01:24 | that means that to make a spike time, you just add up all |
|
01:29 | frequencies from minus infinity to plus add them up with equal weights and |
|
01:35 | all reinforce at T equals zero. they all canceled at all other |
|
01:41 | So that's uh that's what the fourier of a spike use. So let's |
|
01:52 | this source into the in homogeneous wave that we talked about several days |
|
01:58 | And uh so here here's the solution we get uh writing down the |
|
02:09 | you see it's expanding geometrical spreading, got a solitary factor uh that you |
|
02:16 | here and this is exactly the expression we uh wrote before. So there's |
|
02:23 | for the amplitude of the source and is gonna be uh constant. Um |
|
02:29 | gonna be one or you know, a stronger source, it would be |
|
02:32 | stronger constant but still be independent of for an impulsive source. So uh |
|
02:40 | can make the inverse for you, that. It's the inverse fourier |
|
02:46 | Um is uh is gonna give you through the the fourier calculus here And |
|
02:56 | these are zero was here. It's same as evil as this. And |
|
03:03 | when you uh you can look up you, you can look up these |
|
03:08 | um expressions and might be a little difficult for you to follow this fourier |
|
03:17 | inverse transform to get from um uh the spectrum back to uh time |
|
03:27 | But when you do that, the is this and you can see that |
|
03:31 | a delta function, not A. . Equals zero, but it's |
|
03:35 | Equals uh This is equal to um it's equal to one, not at |
|
03:43 | equals zero, but at time equals R or V. So, and |
|
03:49 | a decrease in amplitude as it goes . So it's just an expanding |
|
03:54 | It's a spherical shell of expanding pressure which is zero everywhere in the model |
|
04:06 | for uh at the expanding wavefront, is an impulse expanding at the rate |
|
04:12 | this philosophy. Yeah, so that makes sense that the same. |
|
04:20 | we consider that the medium is is a tentative. And let's assume it's |
|
04:24 | a constant to and no dispersion. dispersion at all. So the fourier |
|
04:30 | solution is this one I want to back and compare with this. All |
|
04:35 | did was we made this uh k here complex. So here uh put |
|
04:42 | right in here, um uh in two and remember uh we've got uh |
|
04:52 | had an I squared in here lead a minus one and we uh um |
|
05:01 | uh converted the real part of the into a real part of V. |
|
05:09 | uh and the freedoms. So making inverse transform of this gives them more |
|
05:18 | result. And you see it's got integral from minus over frequency from minus |
|
05:23 | to zero. And then another uh handle separately the uh the other the |
|
05:30 | frequencies. And if you work out intervals, you find uh that this |
|
05:36 | the answer and it's not an When you, when you graph this |
|
05:44 | , it's not an impulse. And uh furthermore, it's not a it's |
|
05:55 | zero phase wave, it at You can see it's it's uh it's |
|
06:00 | symmetrical, It starts off uh becomes zero here at negative times and the |
|
06:09 | time is given right here, the time has given uh x over |
|
06:18 | Um but it stretches for infinity in directions. And you can uh get |
|
06:25 | poor discussion of this in uh in technical by AKI and Richards, what |
|
06:33 | shows is the energy begins to arrive before the nominal arrival time, thus |
|
06:39 | the principle of causality, see the begins to arrive way back here, |
|
06:45 | you don't expect anything to arrive before before this time. And uh um |
|
06:57 | know, I misspoke, it is I misspoke, I said it was |
|
07:03 | . I said it was not symmetrical it is symmetrical. Uh we call |
|
07:08 | zero phase, whereas real data uh always uh similar shape. It's uh |
|
07:15 | loaded with a long tail extending for times. So we call that minimum |
|
07:20 | . And so these are unfeasible So one or more of our assumptions |
|
07:26 | be invalid. So let's go back look at the assumptions. We only |
|
07:32 | the linear wave equation. So uh in homogeneous equation, but the uniform |
|
07:39 | but the medium is uniform. We this an in homogeneous equation because on |
|
07:44 | right side is the source term, does not have the unknown in |
|
07:49 | That's the source term, That's that's we assume. And we assume constant |
|
07:55 | throughout the entire band. And we constant velocity throughout. And so uh |
|
08:02 | conclusion is that both of these are implausible and what we proved theoretically. |
|
08:12 | and coupled with laboratory data proves that are mathematically impossible. It is when |
|
08:18 | um when we do laboratory experiments on walks, we always find uh frequency |
|
08:26 | Q. And frequency dependent velocity at same time. And so the conclusion |
|
08:32 | because of the second law, Q be finite and positive. Um And |
|
08:41 | that both of these must also be dependent. So despite that it's very |
|
08:50 | because we have limited bandwidth in any . Uh it's uh it's very common |
|
08:58 | to approximate that you and velocity are constant within the seismic band and also |
|
09:08 | any other band you might think Like in the ultrasonic band, we |
|
09:12 | assume the velocities are constant in the band. We assume that the |
|
09:18 | but when we look, when we velocities uh compare velocities across these bands |
|
09:26 | these bands, we expect to find . So uh we expect that the |
|
09:34 | . Is going to be different in seismic van than the ultrasonic band. |
|
09:39 | velocity is gonna be different between Yeah, or whenever you talk about |
|
09:50 | in a serious way, you always involved in ideas of the mechanism |
|
09:56 | Uh And so it's always a messy , you don't ever talk about the |
|
10:04 | of elasticity. You just say, that's the that's the stiffness constant. |
|
10:09 | we always have to talk about mechanisms of insinuation. And so lots of |
|
10:17 | mechanisms have been discussed which are um are inferred to be one or another |
|
10:25 | them is inferred to be dominant in bands. So for example, um |
|
10:32 | the ultrasonic ban, the dominant mechanism attenuation is scattering off of the grain |
|
10:42 | the uh and it's different in other . So um when you do this |
|
10:50 | of analysis you're frequently almost always you that the uh there is a relationship |
|
10:57 | attenuation and dispersion which can be written this way. Take the velocity at |
|
11:02 | different frequencies. Whether their angular frequencies cyclical and you uh reduced, that's |
|
11:13 | linearly proportional to uh log log random law over the ratio of the two |
|
11:21 | . These two frequencies are the same the With the proportionality concept, which |
|
11:27 | one over Pi Q. Now, to see what this implies for seismic |
|
11:33 | take the upper frequency to be 100 , the lower frequency to be 10 |
|
11:39 | . Take your vehicles 50 then the of velocity is here um at the |
|
11:46 | frequencies, putting in these numbers, in 50 right here for the |
|
11:51 | 110 for the two different frequencies. turns out uh The only different from |
|
11:59 | by 1.5%. So that means to this velocity difference across this ban with |
|
12:06 | kinds of Q factors you have to doing. You have to be determined |
|
12:12 | velocities with with accuracy and precision better 1.5%. So that's a tall |
|
12:23 | Now let's do the same situation for partially saturated sediments where we've got a |
|
12:30 | smaller if you factor so now across band it's differing by 15%. So |
|
12:38 | could be measurable. Um Although it true that uh if it's a thin |
|
12:46 | , you might be not be able measure velocities in that thin layer. |
|
12:53 | so the accuracy of 15%. But can see how the in the thin |
|
13:01 | with partially saturated sediments, it's gonna high attenuation, meaning lo que. |
|
13:06 | it's also gonna have high dispersion in case 15% this. Uh And you |
|
13:16 | , because you have this high the the usable bandwidth might be |
|
13:23 | It might be that you can only up to 50 yards. So that |
|
13:28 | decrease this even small. However, you're comparing a Masonic band with the |
|
13:37 | band, then we have a big . Here's a sonic band, uh |
|
13:44 | seismic band frequencies And uh normal Brian's for the Q. And so now |
|
13:50 | see 22% uh writers. So uh the difference between uh not visible within |
|
14:01 | seismic band, not visible within the band. But when you compare velocities |
|
14:06 | two different uh bands. So what means is when you're comparing sonic data |
|
14:15 | um um seismic signing velocities to seismic you've got to be mindful of |
|
14:23 | This difference here, which could be and it's due to intrinsic attenuation In |
|
14:34 | rock in the rocks. And uh assuming it's the same cube right? |
|
14:41 | both cases. And cute. But velocities are gonna be changing by 22% |
|
14:47 | this example. Now take this same here and turn it into uh consider |
|
14:57 | frequencies which are close together and uh frequencies which are close together and consequently |
|
15:06 | velocities are close together. And turn into a differential relationship. And you |
|
15:11 | uh just rearranging this, the inverse Q is proportional to the partial derivative |
|
15:17 | velocity with respect. So here's a since attenuation comes along with dispersion, |
|
15:34 | follows that a higher value of Q larger dispersion. Miss Del rio. |
|
15:41 | that current false? Yeah, that's . Because the display the attenuation goes |
|
15:47 | 1/2. Very good. So so let's talk about some mechanisms of |
|
15:56 | Now when we talk about hook, law, we assumed perfect elasticity. |
|
16:02 | that's not the only relationship between stress strain that you can imagine. And |
|
16:08 | here is a very general relationship between and strain. A generalization of |
|
16:16 | And so here we have the And here we have the modular just |
|
16:20 | we had before in the strain. now we have additional parameters to characteristic |
|
16:26 | time. And so what this says that this this is general that it |
|
16:31 | so long. Still linear. C linear between the stress and the |
|
16:37 | But it says that the this combination stress and the rate of change of |
|
16:44 | is proportional to this. Um uh of strain and the rate of change |
|
16:52 | strain. And you can bet this is gonna be complex. So naturally |
|
17:00 | can see here that Hook's law is special case of this corresponding to assuming |
|
17:05 | two characteristic times R zero. So is called the standard linear salad standard |
|
17:14 | solid. And uh you know, not surprising that we have more complicated |
|
17:21 | between stress and strain that we thought after hook, hook, hook was |
|
17:27 | first one. That was the 17th than a lot of times here for |
|
17:32 | to think about this and managed to about this. And so this is |
|
17:38 | um straightforward generalization of Hook's law to for the possibility of more complex material |
|
17:49 | . And so what you can do you can you can aspire to measure |
|
17:53 | things, um uh real materials with experiments. So as a consequence of |
|
18:03 | , we can say uh we can say the following, look what we |
|
18:08 | here. We have frequency expressed in non dimensional way because it's multiplied |
|
18:15 | you know, frequency has the physical in inverse time. So we multiplied |
|
18:22 | the square of the product of these characteristic times. Then we get a |
|
18:27 | curve here, it looks like so the and the velocity, it looks |
|
18:32 | this actually this square of the velocity low frequency is low, then uh |
|
18:40 | the interval where frequency is comparable to uh to the inverse of these, |
|
18:48 | fine, then it changes and then reaches uh asymptotic limit and goes flat |
|
18:56 | . And so the Q. Is uh proportional to the time derivative of |
|
19:07 | . So uh we showed a couple ago. The inverse of Q. |
|
19:12 | proportional to the time derivative of this here. And so here it |
|
19:18 | It has a peak just where this is changing. And the maximum value |
|
19:25 | the peak is defined in terms of characteristic times. Like so and so |
|
19:31 | either one of those characteristic times is Then the maximum value of few is |
|
19:40 | . See you right here. Uh Let's put some um put this |
|
19:51 | context for sedimentary rocks, the size band is down here, The sonic |
|
19:57 | is right here in the middle and ultrasonic band is here. So normally |
|
20:02 | think that seismic um seismic data occupies mostly flat region. And um ultrasonic |
|
20:11 | in the laboratory occupies this mostly flat . And sonic data is where it's |
|
20:19 | . And so uh of course this just um hand waving a bit because |
|
20:27 | exact uh the exact demarcations between these upon the values of these characters at |
|
20:36 | . Which are going to be different Iraq of course. Uh But that |
|
20:41 | is a general expectation. Um I there are several dispersion mechanisms which which |
|
20:55 | their peaks and they have different time here. So they have their peaks |
|
21:00 | different values of absolute frequency. So you would expect to have this sort |
|
21:06 | thing as a function of frequency. can see there's a superposition of those |
|
21:13 | of of a few functions. So sort of constant here in in the |
|
21:19 | the interim. And uh across that here, that's where the phase velocity |
|
21:25 | changing. And for lower frequencies and frequencies it doesn't change. Now. |
|
21:31 | course, the different dispersion mechanisms could um uh different absolute values of the |
|
21:44 | . And so maybe this is not , but you can see we are |
|
21:47 | limited to think of only peaks like . You can superimpose those sorts of |
|
21:57 | , Pete's with several different different mechanisms in the rock at various frequencies. |
|
22:03 | Each one of these is dominant, frequencies. So in the example from |
|
22:08 | and Richards, it ended up with phase velocity curve which was linear. |
|
22:14 | course, that's just a cartoon. you see the idea uh you can |
|
22:21 | in a real rock. The superposition many um many types of linear continuation |
|
22:35 | like I showed on the previous. for each one of them it's gonna |
|
22:42 | upon which mechanism of the generation depends the frequency. So, so you |
|
22:49 | to sonic frequencies take my word for . The dominant mode of attenuation is |
|
22:54 | fluid squirt within the pore space as p wave goes through it. Um |
|
23:03 | is the uh different parts of the pore space unequally because the pore space |
|
23:09 | a complicated shape and so parts of are thin and flat. So those |
|
23:14 | are calling cracks and they more They respond to the pressure in the |
|
23:22 | of of longitudinal stress that gets converted um in the fluid to a |
|
23:31 | And that's um um That stress affects cracks more than the round ports or |
|
23:41 | roundish ports. Of course there are spherical pores anywhere, but there are |
|
23:45 | which are more or less um equal in all dimensions. Whereas the crack |
|
23:51 | ports are defined to be those which much smaller dimension in one direction than |
|
23:57 | the other one or two directions. since the pore space is gonna be |
|
24:07 | to the imposed stress in this complicated , that means that fluid is going |
|
24:12 | be squirting from different parts of the pore space to other parts, from |
|
24:18 | cracks to the pores during the compression and the reverse in the decompression |
|
24:25 | And the word squirt is a little um overdramatic because uh the fluid doesn't |
|
24:36 | to move very far to equalize the . Okay, Just um especially from |
|
24:44 | crack to the nearest four. By , ultrasonic frequencies which are greater than |
|
24:54 | hertz. Um The dominant mode of generation is scattered from the grains. |
|
25:02 | in the seismic band. They man, we're talking about now, |
|
25:11 | strength of the squirt mechanism. That the amount of the dispersion it |
|
25:16 | and the amount of attenuation it causes on the fluid. If the pore |
|
25:22 | partially saturated with the oil, then squirt mechanism is enhanced because of the |
|
25:29 | viscosity of the oil. As the squirts from the crack to the forest |
|
25:35 | more energy to heat because of the viscosity of the oil. Furthermore, |
|
25:44 | the pore spaces partially saturated with free , then the squirt mechanism is greatly |
|
25:50 | basically because the gas gives the fluid uh space to squirt into. Does |
|
26:01 | make sense? If there's gas partial in the park space, Then when |
|
26:06 | fluid squirts around, um It's It can do so easier because it's |
|
26:12 | being resisted by fluid, which is there, there's some uh gas in |
|
26:18 | other part of the portion. So in these two context um the uh |
|
26:27 | . Factor for p waves is but two factor for share waves is |
|
26:33 | because when share wave goes to it does not compress the rock at |
|
26:39 | . It just tears a lot so uh there's no squirting of the fluid |
|
26:46 | um uh escorting. It's uh it's lot less than if there is a |
|
26:53 | being applied. So um this problem a particular interest to me because of |
|
27:04 | experience at uh as an Amoco long ago, maybe before you all were |
|
27:12 | . Um I was working for Amoco um Tulsa at the research center for |
|
27:21 | of my career with american. I in Tulsa, but at a certain |
|
27:26 | I moved to Houston Uh to the offices in Houston, which are out |
|
27:33 | of downtown near I 10 and Eldridge . And there we have, that's |
|
27:44 | um worldwide headquarters of Amoco's Exploration. now it's uh since BP bought |
|
27:56 | that's now worldwide headquarters from BP Exploration in London. And so the Houston |
|
28:04 | is I think the largest, I it's even larger than the our people |
|
28:10 | project. This data was acquired in american base and this data was |
|
28:19 | This is conventional p wave data um by Amoco uh in the early nineties |
|
28:30 | processed with the state of the art imaging from those days. And it |
|
28:36 | called a D. M. Stack. And so I'll leave it |
|
28:39 | your other professors to explain what uh that is. And so here is |
|
28:47 | reservoir down here and you can see fairly well imaged here and right in |
|
28:53 | middle it disappears and then off to side. So uh this reservoir, |
|
29:06 | prospect was discovered by Amoco In the 90s or maybe the late 80's and |
|
29:14 | saw this huge hole in the image they had no idea what it |
|
29:25 | they could uh depending on what well for for several years, they |
|
29:34 | everything they knew to get a better here in the middle. And and |
|
29:41 | um let me just give you a context. This is a limestone |
|
29:47 | Jurassic age and sediments above. And can see that it's a time section |
|
29:54 | . So this is almost three seconds this is halfway down. So above |
|
29:59 | , it looks quite normal. But at and just above the reservoir, |
|
30:07 | has this huge hole in it. eventually they got their nerve to drill |
|
30:12 | this. Can you imagine being um the drilling crew that went to drill |
|
30:20 | hole here. You know, you're into a monster, but you don't |
|
30:25 | what it is. Uh when you when you leave home to sail out |
|
30:32 | to drill this, you wanna kiss spouse tenderly goodbye and make sure your |
|
30:39 | is paid up because you might not come back from this drilling okay. |
|
30:47 | . So they did drill it. they found a very nice discovery. |
|
30:53 | found a billion barrel oil field So, that was years before I |
|
30:58 | involved. But I got involved in mid-90s because they could not make an |
|
31:04 | of this. So, our modern of this is that this lack of |
|
31:17 | quality in here comes from attenuation. understanding is that over time, over |
|
31:26 | time, the reservoir, which this a time section. So these velocities |
|
31:31 | been pushed down. Actually, these have been pushed down by uh slow |
|
31:39 | and you can see up here that doesn't happen. So, evidently the |
|
31:45 | down is happening, happening, starting with this layer here. And the |
|
31:53 | understanding is an over geologic time gas leaked up out of the reservoir, |
|
32:00 | accumulating in the overburden here. We know that um uh the reservoir looks |
|
32:07 | a broad shallow dome here, like , and that the imaging quality here |
|
32:12 | so poor because over geologic time gasses up out of the reservoir collected in |
|
32:20 | overburden here. And the effect of gas is to slow down the p |
|
32:27 | , you can see here, this in time, not a depression in |
|
32:33 | . Uh we got a uh huh section as opposed to a time |
|
32:41 | this would be just flat across So, the effect of this gas |
|
32:49 | is to slow the waves down and attenuate them. So you cannot make |
|
32:55 | a good image with this kind of . And uh so for a number |
|
33:03 | years, uh we thought, we just need better imaging uh need |
|
33:07 | do better than the and so, now the imaging technology has increased dramatically |
|
33:14 | then, and now we would try tm the first time migration on |
|
33:20 | but we would still find it would better than this, but it's still |
|
33:24 | bad because the arrivals simply aren't The energy got um disappearing out of |
|
33:36 | P wave by this uh gas saturation the overburden over the crest of the |
|
33:47 | . Yeah. Um the uh guess exist in this region in non economic |
|
34:01 | , just a few percent. So don't think even today that we can |
|
34:05 | any money by producing this gas, we can make a lot of money |
|
34:12 | figuring out how to make an image the reservoir despite this problem. And |
|
34:19 | where I came in and I was in solving that problem for ethical, |
|
34:24 | I'll show you later to know, a diagram of what's happening. We've |
|
34:30 | a P wave going down through uh on the outside of the cloud of |
|
34:37 | . And as it comes back it disappears because it's attenuated away by |
|
34:44 | high by the low value of Inside the gas. Now, about |
|
34:54 | the mid nineties, we had the that if you use converted wives, |
|
35:00 | could send a P wave down through and and let it um convert to |
|
35:11 | at this point, and this shear is gonna go up without being affected |
|
35:16 | the gas lamp. Now, of , there's uh, there's a share |
|
35:23 | convert here too. But remember the wave comes up at a steeper angle |
|
35:29 | the P wave goes down because the is long. So the shear wave |
|
35:35 | at this point is gonna come up an angle like this is gonna be |
|
35:39 | over here. It's not going to through the gas club. Uh, |
|
35:42 | conversion point in this case is over . And so uh do a survey |
|
35:49 | used converted wave energy to uh instead the p wave energy, which didn't |
|
35:57 | it. Maybe we can make a image. So what do we have |
|
36:01 | do to do a converted wave in two marine environments? We have to |
|
36:05 | a P wave source. But to uh receive this sheer way. What |
|
36:11 | have to have is ocean bottom seismic with horizontal components. And this year |
|
36:18 | coming up is going to have gonna polarized trans version. So it's gonna |
|
36:24 | polarized almost horizontally in this cartoon. course it would be like, so |
|
36:28 | exactly horizontally, but almost. And that's what we need ocean bottom seismic |
|
36:36 | , receivers with horizontal components. So we did that, um, that |
|
36:44 | uh from my team that that imaging a couple of years later in |
|
36:49 | we got uh this image here and was the first image that had ever |
|
37:00 | the first usable in it had ever made Valhol. So when I, |
|
37:07 | I went over to uh give honor the chemical offices in the chemical in |
|
37:15 | Norwegian oil capital Post of Honor on northwest coast of Norway. That's where |
|
37:22 | Amoco offices are. That's where all oil companies all the oil companies |
|
37:29 | So I gave uh showed them this , uh and these were guys who |
|
37:34 | spent the previous decade trying to produce from without ever seeing it adequately. |
|
37:42 | they stood and applauded when when they this, it was a fantastic |
|
37:48 | And my colleague over there was Olaf and uh he's still a good friend |
|
37:56 | I saw him this summer, past in Madrid. He didn't come to |
|
38:00 | SPG meeting uh two weeks ago here Houston, but I saw him in |
|
38:05 | , he's doing well. That would P anymore. So um let's see |
|
38:13 | . Uh you can see it's not perfect uh figure, but everything that |
|
38:19 | see in this figure is confirmed by bits. And so uh this is |
|
38:26 | figure that we showed to uh and sent it back to us with these |
|
38:32 | oil wells put in there and he the oil wells confirmed all the details |
|
38:38 | are imaging showed. Well, this in 1996. And uh this is |
|
38:45 | normal murat processing basically basically dicks um move out removal and stacking is all |
|
38:53 | did. And we got this this pretty good image, we can |
|
38:57 | much better images today with better um processing algorithms and done by people who |
|
39:06 | smarter at image making than I Um but the essential idea we had |
|
39:13 | to use the converted way of arrival of the P waver. So let |
|
39:23 | uh pause here and tell you a of stories associated with this image on |
|
39:31 | bottom. Seismic imaging was invented not Amoco, but by statoil, the |
|
39:38 | state oil company, which is now Ecuador. And they invented it about |
|
39:44 | in 1990 for something like that. they gave up um a talk |
|
39:51 | and the reason they did this was had a Uh reservoir of their |
|
39:57 | about 50 miles from Valhol in the Southern North Sea with a similar |
|
40:06 | a gas cloud in the older And they had the idea that if |
|
40:09 | were just Hughes could hurt a wave , they could see through the gas |
|
40:16 | . And so they, um, they invented ocean bottom seismic recording with |
|
40:29 | components. I should tell you that , there had been a previous version |
|
40:34 | ocean bottom seismometers with only a vertical and a hydrophone. And like we |
|
40:41 | you before, um, uh, need two of those, uh, |
|
40:46 | combine the two components together to eliminate water bottom multiple. What Seattle did |
|
40:56 | to uh, generalize that horizontal components back up to this line here. |
|
41:05 | presented their um, mhm results of there reservoir At the European Association |
|
41:20 | I think in 1994. And it a big hit. And I think |
|
41:26 | won an award for the best paper there and I was not there, |
|
41:32 | was in Geneva, the european Association gives their conventions in europe. And |
|
41:42 | I was not there, but my was there and he came back and |
|
41:46 | me all about it and he said you know, we can do something |
|
41:54 | that. And within a week or we had a phone call from our |
|
41:59 | in the Norway office and they said know, we have a field just |
|
42:04 | that state all field and we want uh um we want to image him |
|
42:14 | the same way they did. Would help us? So we're operations here |
|
42:20 | this, we need the help from experts in Houston. Well, I |
|
42:25 | in Houston at that time in the department. And so we uh talked |
|
42:33 | ourselves and and we said, you , this is really an interesting |
|
42:36 | We've never seen any data like this . Um but that's a research |
|
42:43 | And our our task in Amoco is exploration support, not research. So |
|
42:53 | sent this problem to our friends up Tulsa and they said we said you |
|
42:59 | should help out the Norway office to that. Well, we had a |
|
43:04 | vice president of research in Tulsa and was one of the reasons why I |
|
43:10 | Tulsa and moved to Houston and he imposed a system on them which made |
|
43:17 | uh promised to make uh to work specific problems and to yield specific results |
|
43:26 | a specific time frame. No no excuses, admitted. And so |
|
43:34 | wrote back to us or they told on the phone. Sorry. We |
|
43:37 | , we promised to work on this project. We don't have any time |
|
43:41 | this converted wave project. Sorry. we went to my boss in Houston |
|
43:49 | and he said, well and told what happened. And he said, |
|
43:53 | , you guys should do it And we said, you know, |
|
43:57 | we do that, that's research. going to be criticized by the Vice |
|
44:01 | for research up in Tulsa for stepping his toes. And so my supervisor |
|
44:07 | exploration in Houston said, never mind vice president for research. You guys |
|
44:13 | go ahead and do whatever you think best for the company. Just keep |
|
44:17 | informed so I can get you the need. Don't worry about the Vice |
|
44:23 | for research. So we did that produced this uh, reach your |
|
44:31 | But I'm skipping ahead of the Um Take yourself back to Geneva in |
|
44:43 | when Stotler was presenting their results which , you know, comparable to this |
|
44:49 | their field. And the uh, I said, I was not |
|
44:55 | but in the fall that same year came to the Sug convention and showed |
|
45:03 | same analysis and I was there for one. In fact, I was |
|
45:08 | the session in which they presented and was actually not uh not the folks |
|
45:13 | Seattle it was from the processing company was Western Chico now part of |
|
45:21 | So the western Zico uh speaker gave spiel and I'm sitting there at the |
|
45:26 | table thinking wow this is really My buddy was correct. This is |
|
45:31 | stuff. And then at the end applause and after the applause died down |
|
45:37 | buddy stood up at the back of hall and he said, wait a |
|
45:42 | you are presenting this uh analysis in of these converted waves that we see |
|
45:53 | . But isn't it true that just months ago in Geneva you presented an |
|
45:58 | of the very same data set where said that the conversion was from Peter |
|
46:04 | at the ocean bottom surface right here down as a share way and converting |
|
46:10 | not converting here coming up as a wave shear wave all the way. |
|
46:16 | you describe the same analysis analysis of same data set in terms of completely |
|
46:24 | , they bad. And I've never a speaker as embarrassed as that and |
|
46:30 | said yes, that's true. I hoping nobody would notice. And so |
|
46:36 | buddies back in the back of the he said uh well um uh so |
|
46:44 | did you change your mind? And said, well uh we designed the |
|
46:51 | knowing that the velocity ratio in these here was about two p waves twice |
|
46:57 | fast as share waves. And so we did our survey and received the |
|
47:02 | on the horizontal components over here, uh found a strong arrival about twice |
|
47:09 | p wave arrival times. The shear are arriving about twice. So we |
|
47:15 | we had it nailed and that's what presented in Geneva. She waved down |
|
47:23 | shear wave up. But then when got home to the home office, |
|
47:26 | happened to talk about some talk of of our wire line buddies and they |
|
47:32 | to us that in these kinds of , the velocities are about velocity ratio |
|
47:36 | about three times here. So that that the shear wave down, shear |
|
47:41 | up is gonna be coming in way . So just put some numbers, |
|
47:45 | about the p wave arrival comes in three seconds. And so the sheer |
|
47:52 | rival should have been coming in or , nine seconds. What they found |
|
47:55 | something coming in at six seconds halfway between. So obviously it's P down |
|
48:00 | sl so he said, once we that the velocity ratio here is so |
|
48:05 | higher. Then we were driven to explanation that the conversion happens here, |
|
48:13 | at the surface, not at the floor. So my buddies at the |
|
48:17 | of the wall, he back of hall, he doesn't let it |
|
48:20 | He says, so show us the at nine seconds for the pure share |
|
48:28 | . And they said um, oh we we we cut off our recording |
|
48:37 | at seven seconds because we knew you looking for something at six seconds. |
|
48:43 | about that. They only saved two per shot of recording time. And |
|
48:49 | course there's expenses associated with two seconds additional recording. What um, |
|
48:59 | they had many, many shots so would have amounted to a significant increase |
|
49:03 | the budget. And so in order be efficient, they Cut off the |
|
49:10 | at seven seconds and so they completely dis analyze the whole situation. So |
|
49:19 | a lesson for you young people when doing something for the first time, |
|
49:23 | don't design the uh the process to efficient. You designed to make sure |
|
49:29 | you come back with the answers that want. So when we went out |
|
49:34 | a few months later to do the experiment at home, we recorded for |
|
49:38 | seconds. And sure enough we saw at nine seconds, nothing at 12 |
|
49:44 | . We saw something in nine seconds it was very weak. And we |
|
49:48 | what everybody has to put it ever the most energetic convert away of arrivals |
|
49:53 | happening conversion here rather than at the . So then it took us a |
|
49:59 | time to figure out all this uh effects of uh converted way of uh |
|
50:09 | . And we talked a little bit that earlier in the forest, we'll |
|
50:12 | a little bit more about it uh because not tomorrow, but next friday |
|
50:20 | it turns out that anise actually plays important role. So uh before I |
|
50:30 | on, I want to tell you uh I learned later much later that |
|
50:38 | we found success before we found success this, the Vice president for research |
|
50:47 | complain to my boss in Houston. , I was not there. But |
|
50:53 | heard the story later. The vice complained to my boss who was three |
|
50:59 | lower than him in the R And he said you guys are out |
|
51:03 | line here. Research is my not yours, your your businesses applications |
|
51:10 | the exploration department. And so my had the courage to say to the |
|
51:14 | president, he said, well you set up a system that cripples |
|
51:18 | people so we can't so they can't to challenges like that. So we're |
|
51:23 | do it here. Huh? um you can imagine that the vice |
|
51:30 | was pissed at this response from this level manager. So no doubt he |
|
51:37 | to my boss's boss was Vice president Exploration in Houston. So that guy |
|
51:43 | not know me but he knew my and he backed him up. And |
|
51:47 | we went ahead and did the But I'm I can assure you that |
|
51:50 | we had not had this kind of , both scientifically and commercially for the |
|
51:56 | business unit, we would all been and I would not be sitting here |
|
52:00 | to you today. So I want tell you one more interesting story along |
|
52:07 | lines about a year later one of colleagues at a medical came to me |
|
52:15 | a confession and he said leon I've uh trying to image this Reservoir using |
|
52:25 | wave data for the past year by velocities and so on and adjusting the |
|
52:31 | model. He said I tried I 80 different variations velocities and imaging algorithms |
|
52:39 | everything. None of it um So he said you guys had this |
|
52:47 | with your very first try, very . Uh We were we were very |
|
52:52 | in all the stages here were much sophisticated these days you guys had success |
|
52:58 | we were willing to think of this a converted wave problem different in uh |
|
53:04 | many ways from a P wave And he was thinking that all we |
|
53:08 | to do was the justice thinking a bit. And he would find success |
|
53:13 | classical methods. And we said uh said to ourselves, we're gonna throw |
|
53:19 | the uh the recipe book and start about this problem from first principles. |
|
53:26 | in fact we did invent many new for conferred wave processing which are showing |
|
53:32 | here and I'll tell you more about . Um Next friday because a lot |
|
53:40 | it involves. And I started so look at this quiz was five to |
|
53:56 | time for sedimentary rocks. The dominant of attenuation in the sighting band is |
|
54:03 | fluid flow. Well, we already that that that one is true. |
|
54:10 | then you saw from the previous figure from the previous discussion that um the |
|
54:21 | is enhanced. This same mechanism is that gas is present in the four |
|
54:26 | . That's what you see right? here, but uh you see it |
|
54:32 | uh the previous image for p ways one data quality just disappeared here because |
|
54:44 | enhanced attenuation of the p waves due uh squirt global squirt flaw enhanced by |
|
54:52 | partial saturation. That's so that was true. Uh And we also saw |
|
55:03 | one's true. If we look at wave data, we might get images |
|
55:07 | are better in those freeways. And uh not necessarily, but maybe. |
|
55:13 | we saw in this example that was also. So now I want to |
|
55:20 | about apparent continuation and let me check time here. It's now 2.30. |
|
55:27 | so this is a good time for take a break. So let's come |
|
55:32 | at 2:45 and we'll talk about apparent . Mhm. So now after the |
|
55:42 | we're going to resume where we left with apparent attenuation. See how this |
|
55:48 | is italicized. Uh Somehow when I it like this, it doesn't respond |
|
55:56 | the controls. So I have to um I'm gonna try this and try |
|
56:09 | . And now here the screen see if it works this time. |
|
56:23 | , sharing the screen and now the work. Okay, remember from the |
|
56:30 | lecture we were deriving the scalar wave and here's some stuff that we um |
|
56:38 | did before and we we we came to this part where we're taking a |
|
56:44 | with respect to this uh combination which is basically the stress. And |
|
56:53 | that point we assumed that the the medium was uniform and we brought |
|
56:58 | thing outside of the uh derivative and it over here and now the derivative |
|
57:05 | is right here operating on this. you can see it's not yet, |
|
57:10 | wave equation, you can see there three space derivatives here and both space |
|
57:16 | time derivatives over here. So it some further work to get the wave |
|
57:22 | out of this, but I want concentrate on this step right here because |
|
57:28 | know the medium is not uniform, not even piecewise uniform. Normally in |
|
57:35 | business, we assume that it's piecewise and we solve the wave equation inside |
|
57:44 | piece separately. And then we handle intersection between the different uh pieces with |
|
57:58 | condition and we get reflections and refraction all that. But now I want |
|
58:03 | recognize that it's um that whole process uh not really the way to approach |
|
58:14 | Earth because the Earth has in homogeneity all scales. And so you can't |
|
58:22 | any place in the Earth which is uniform even on a small scale of |
|
58:28 | , right? There's the grains and , there's an in homogeneity. And |
|
58:33 | uh we're gonna think about in homogeneity on a larger scale, on the |
|
58:39 | scale next. So without making that when we moved from here to the |
|
58:48 | line and we get a term like did before plus uh this additional term |
|
58:53 | comes from the derivative of the stiffness with respect to X. J. |
|
58:58 | like it says in it, it's changeable calculus. So this is a |
|
59:02 | new term. So now we're going see how this term, because of |
|
59:10 | non uniformity of the media leads to attenuation. So uh you can see |
|
59:18 | in the general case it's gonna be complicated. So let's simplify ourselves down |
|
59:23 | vertical p wave propagation. And so vertical p wave propagation, the previous |
|
59:29 | simplifies to this. You can see this part is the wave equation that |
|
59:33 | saw before. And now we have additional term which comes from the derivative |
|
59:40 | the displacement. Uh comes the derivative the stiffness element with respect to um |
|
59:50 | distributive here of the vertical component of . That's just this one over |
|
59:57 | Yeah. So uh new things come because of this. So this makes |
|
60:06 | wave just like we talked about that this term is going to lead to |
|
60:11 | attenuation. We're going to assume that here is real. So uh ignore |
|
60:17 | we did earlier about. Uh complex module I I want to abandon uh |
|
60:25 | discussion of those complications, revert back the elastic case and think about how |
|
60:32 | gonna get apparent continuation out of perfectly media. This number is real. |
|
60:40 | as before we're going to assume a wave solution. And so here we |
|
60:45 | a set three, that's a that's the vertical component of the wave |
|
60:52 | . And we're gonna put this into equation of motion. And when we |
|
60:56 | we do that, that guess at solution then in that case there's two |
|
61:03 | with respect to depth results and and two factors of minus I k three |
|
61:12 | here minus I K three in the exponent leads this and in the same |
|
61:21 | we get one factor minus I k coming from this term. Right |
|
61:29 | there it is. Now, this a quadratic equation for K three. |
|
61:36 | uh where do we see that? rearranging terms? We uh we get |
|
61:46 | this uh a three squared comes from . K three to the first power |
|
61:51 | from here, and K three to zero power comes from here. And |
|
61:55 | notice that the coefficient here is imaginary before, when we ignored the in |
|
62:03 | of the medium, this term was and we just said V p squared |
|
62:09 | squared equals omega square. And that old old to you now. But |
|
62:15 | this is something new coming from this here. This is not zero. |
|
62:22 | . So I said before soon that meeting is perfectly elastic so that the |
|
62:30 | lunch, general element assistant settlement M real. Now the solution to that |
|
62:36 | equation is given by this. Uh knows how to solve a quadratic |
|
62:42 | And so because of that, three is complex even though M is |
|
62:50 | . So this quantity here comes Well you can see it's it's got |
|
62:57 | partial F. With respect to So that was zero before and it |
|
63:03 | before it was zero here and it zero here. So we got the |
|
63:08 | expression K three equals America over vp now it's not zero even though uh |
|
63:17 | non zero um uh part, let say it again, A three is |
|
63:26 | because of this, even though M real. Now in this expression, |
|
63:34 | that the velocity and the stiffness are of the medium, not of the |
|
63:39 | . K is the property of the , but M and V P. |
|
63:44 | . Properties of media. So the is specified by frequency and the choice |
|
63:50 | algebraic sign right here. So we think about propagation in the plus the |
|
63:57 | . So we select the plus sign here. Now what we're gonna do |
|
64:05 | what we do so often is to a taylor approximation and assume that these |
|
64:11 | are small in that case the square simplifies. So this linear term and |
|
64:19 | brings in a factor of -1 Where does that come from? The |
|
64:23 | comes from here and the one half from the square root and we still |
|
64:27 | this square. This quantity is going be a soon to be small. |
|
64:34 | just to make further progress, we understand what this is telling us. |
|
64:38 | make this approximation, then we average over a wavelength. And so uh |
|
64:45 | we average it over a wavelength uh This is average here, that's this |
|
64:51 | here and this gets average. That's one here. And you can see |
|
64:57 | I've done is I've multiplied this out that the omega over V. |
|
65:01 | Uh multiplied by one this term. then you get um um uh makeover |
|
65:11 | times this stuff. Uh Simple planks this, you still have omega in |
|
65:19 | ah in the Denominator here because there's omega squared here, multiplied by an |
|
65:26 | here still leaves one omega down The real part is given by this |
|
65:32 | the imaginary part is given by So this here is what we previously |
|
65:39 | the friendly multiple delay. So the that this is squared here. That |
|
65:44 | from the fact that um there's two to additional reflections in a friendly |
|
65:50 | And we talked about this friendly multiple um before a lot. And so |
|
65:59 | here it shows up again in this and it's all consistent with what we |
|
66:05 | before. So putting that all into , we have the plane wave solution |
|
66:13 | like this. Um This is the part of K three is here and |
|
66:19 | backup, here's the real part, what it says right here, the |
|
66:23 | part. And then plus I times imaginary part. So the imaginary part |
|
66:28 | showing here and IMUIM multiplied the two I together. So we got a |
|
66:36 | here. And so uh here we uh term uh leads to propagation is |
|
66:43 | we did before. And here is term leading to apparent continuation. You |
|
66:47 | see that it's getting smaller as Z . This factor is getting smaller compared |
|
66:54 | of this minus sign. But actually does depend upon this average of uh |
|
67:01 | variation uh element in. So let's a case where the stiffness shows a |
|
67:13 | . So uh any limited zone in subsurface, is it? Uh can |
|
67:19 | that the uh layers having increasing stiffness them. So in that case this |
|
67:26 | greater than zero. And this leads exponential decay in Canada frequency. It's |
|
67:33 | real or generation, but that's how decay of amplitude, even though in |
|
67:42 | no truer generation, I suppose the is moving the other way upwards. |
|
67:49 | uh so we're gonna obligation of the c direction. We select minus sign |
|
67:57 | the same sign for the imaginary term . And if the variation is small |
|
68:02 | gets to this simplification. And um in the same case where the stiffness |
|
68:12 | a positive trend, the apparent generation is still what we said before, |
|
68:17 | now Z is decreasing so his Z smaller and smaller. The amplitude growth |
|
68:29 | . So is this a problem? , it's not really a problem because |
|
68:32 | only happens over a limited range of in the um in the earth. |
|
68:43 | uh in this case what happens on way up, reverse is what happens |
|
68:49 | the way down. That doesn't happen true attenuation. Uh But it happens |
|
68:56 | this case with apparent continuation. So this case for two way to travel |
|
69:01 | this zone, the apparent continuation cancels . So that was for the case |
|
69:09 | a trend. Now let's case let's a case where the stiffness fluctuates up |
|
69:14 | down with no trend. Then the part of of uh okay, vanishes |
|
69:22 | uh if this thing is fluctuating up down with no training, the average |
|
69:26 | going to be zero and the real is frequency dependent. Um like we |
|
69:35 | before, so notice here, the average of the square of the fluctuation |
|
69:42 | non zero, the, the average the fluctuation because designed designed to be |
|
69:49 | to be zero. Since we're assuming this special application we've assumed no |
|
69:56 | So Average is two but the square that imaginary part does not average. |
|
70:06 | now just to be sort of more more explicit, let's assume uh periodically |
|
70:16 | a cycling value of of business. this is not um This is not |
|
70:26 | with uh finite jumps between the This is uh cyclical uh variation with |
|
70:38 | and co signs. And it's gonna an amplitude of the variation given by |
|
70:45 | M. And it's got a special of the variation given by H. |
|
70:53 | is uh after bed thickness, two travel time magazines. And in those |
|
70:59 | that case the stiffness derivatives given Um It's simply the derivative of |
|
71:06 | It's I times two pi over eight I time over eight. Same delta |
|
71:15 | gives the amount of the variation within cyclical in the wave vector. Uh |
|
71:23 | that into here. The wave vector uh this run by this. And |
|
71:30 | at high frequency this term goes Why? Because of high frequency omega |
|
71:36 | a large, is in the So at high frequency this goes away |
|
71:42 | we're left with this term only. that's the high frequency. So the |
|
71:50 | frequency of velocity is given by uh over k. High which is one |
|
71:58 | the average run. Uh huh. am velocity which is here, I |
|
72:06 | it wrong, this is the average of the slowness To the £-1. |
|
72:14 | this is what we're averaging is not . We're averaging slowness. This is |
|
72:18 | like uh in rate theory, the is given by the average of the |
|
72:25 | . Yeah, that's what it says . This is the very theory result |
|
72:28 | we found and here it is. Do this from huh. Which for |
|
72:40 | low frequency uh This is gonna be bigger because this term here is gonna |
|
72:51 | not negligent. And why is it necklace? Will uh This this value |
|
72:59 | not so high as it was before this uh this is positive and we |
|
73:04 | a plus here. And so the frequency phase velocity is lower because it's |
|
73:10 | know, dependent on omega over Low, here's que lo And so |
|
73:15 | phrase velocity is small is different from high frequency phase velocity because of this |
|
73:24 | here. And this minus sign comes the fact that uh this is the |
|
73:30 | of this. This plus turns into minus when we divide by uh |
|
73:37 | And this is the only multiple people that we talked about. Yeah. |
|
73:45 | there's more to be said. Uh . We've just established that the p |
|
73:54 | loss varies in frequency so there must apparent attenuation. So the very assuring |
|
74:00 | is given by this that just comes differentiating this. And so the parents |
|
74:08 | factor is related to the chill Oh yeah. Oh dispersion. Here's |
|
74:16 | dispersion and mm hmm. Uh the q. Factors related to that by |
|
74:24 | expression. And so it's non zero um the apparent continuation. We can |
|
74:33 | this the apparent attenuation due to the multiple effect. Because of this. |
|
74:38 | frequencies decay more rapidly than low Just as we just as in the |
|
74:45 | with real attenuation. Even though in analysis there is no attenuation at |
|
74:51 | All of these stiffness elements present because the material fluctuations leading to friendly multiple |
|
75:01 | . That's gonna be a function of . And it's going to lead to |
|
75:05 | apparent continuation factor. You invite that MS del rio. It says here |
|
75:22 | of motion leads in the case of betting to these things or maybe all |
|
75:27 | the above. So what do you here? I think it's only be |
|
75:36 | . Mhm. This here is We know it has. We know |
|
75:51 | apparent continuation. That's that's easy. how about a lower frequencies and |
|
75:57 | lower velocities and higher frequencies. it's higher velocities and higher. |
|
76:03 | okay. Yeah. So uh he correct. Well done. So here |
|
76:08 | the conclusions from today's uh from this on attenuation No one. It's important |
|
76:15 | deal with frequently ignore it. But really is important. It causes the |
|
76:24 | loss of high frequencies as a result propagation through a genuine meeting. Always |
|
76:31 | by dispersion. And there are many physical mechanisms. So each one is |
|
76:38 | in one or another banda wave propagation in the in the band from ST |
|
76:45 | to sonic. The most important is flow. Also called fluids. For |
|
76:53 | addition to the velocities, the attenuation at reflectors cause the phase shift in |
|
77:00 | reflected wave. And sometimes that can significant. And finally non uniform media |
|
77:07 | apparent attenuation, whether or not there's reality. And in the special case |
|
77:18 | the where the non uniform media is , we get associated dispersion. |
|
77:29 | The transitional statement is the same, that leads to apparent attenuation also leads |
|
77:35 | anti sergeant, which is the last in this series here, remember what |
|
77:42 | did was we looked in the first lectures here, we did classical racing |
|
77:46 | . Classical raising ways. And then realized that some of the assumptions that |
|
77:52 | had made were not very realistic. we want to apply to Ocs. |
|
77:58 | we looked for elasticity, we wanted continue imperfect elasticity. So we just |
|
78:05 | that and now we turn our attention an icicle. So I'm gonna stop |
|
78:12 | and I'm gonna stop sharing. And think I want to just continue since |
|
78:18 | just now uh getting back together and I happen to have uh next |
|
78:29 | I'll cheat up right here. That works. It works. And |
|
78:39 | into presentation node. and so less 10 anti circuit. So here's our |
|
78:48 | objectives. By the end of this , you will know how to describe |
|
78:53 | common classes of anti psychotropic. You'll to learn how to find the wave |
|
78:59 | for the simplest case, which we polar and isotopic. Then you're gonna |
|
79:06 | exact solutions and then you're gonna find solutions in the case where the anti |
|
79:12 | is weak. Then you're gonna learn these anti psychotropic parameters appear in seismic |
|
79:19 | as we make the transition to weak . We're going to define new parameters |
|
79:25 | we have not yet seen. And gonna see how those appear in your |
|
79:31 | . And we're gonna see how anti affects P wave reflectivity, it affects |
|
79:37 | p wave real problem in a strong , even though the anisotropy is weak |
|
79:44 | how it affects share waves in a way and how it affects convertible waits |
|
79:50 | a fundamental. So that's a lot stuff. Good things. We |
|
79:55 | we have about five or six hours go through this. So the first |
|
80:02 | we're gonna do is tensor elasticity. I remind you that all of the |
|
80:08 | has been classic seismology equally suitable for or for understanding the deep interior. |
|
80:16 | now we know that none of it truly suitable for either case, since |
|
80:21 | ignored the effect of an eye socket out that most sediments are not massive |
|
80:29 | stones like this. But the equations they are right. The the equations |
|
80:35 | psychotropic media but most settlements are not this. Uh does anybody know where |
|
80:43 | rock is? You should know where rock is. A very famous |
|
80:53 | This is in the middle of So it's about very close to the |
|
80:58 | geometrical middle of Australia. And uh Australians call it Ayers rock for |
|
81:06 | But I suspect that the the aboriginal knew it was there before the Europeans |
|
81:12 | , and in fact they have a for it, it's called U |
|
81:19 | U R. U. And I'm sure how that translates. But um |
|
81:25 | the first thing you're about, so our equations assume that the rocks |
|
81:32 | like this in the subsurface, but fact they look more like this. |
|
81:37 | And uh it says here they're normally because you know, we're gonna be |
|
81:43 | these many layers with assigning wave which which is much longer than the average |
|
81:51 | there uh than the average layer So um uh it's gonna experience this |
|
82:00 | layering as an average, right? it's obviously gonna be a different average |
|
82:05 | or horizontal or whatever. Now um might say, okay right here we |
|
82:13 | uh sequence of layers which are more less the same, and we're gonna |
|
82:20 | those as an uniform and I see layer, and then we have a |
|
82:24 | boundary and another block type underneath this slope of weather debris. And then |
|
82:33 | I'm gonna call this is uh another uniform uh formation, And then there's |
|
82:42 | one up here. So, that be a typical uh way of thinking |
|
82:47 | these kinds of rock is piecewise But recognizing that within each layer it |
|
82:56 | be anti subtropical. Well, there might be other small scale features |
|
83:04 | than a wavelength, which might show in a data. You see these |
|
83:09 | fractures here and you can you see vertical fracture uh as half of the |
|
83:16 | , and the other half fell off the lake. And here you see |
|
83:19 | parallel fracture uh also fell in. see a second set of fractures here |
|
83:32 | this one. This whole thing is a vertical fracture where the other half |
|
83:38 | it fell into the lake out of screen towards you. So, these |
|
83:43 | small scale features with preferred orientations, are gonna make the rock mass with |
|
83:51 | as an average over seismic wave It's gonna make it. Um So |
|
83:59 | Nature tells us that all rock masses this kind of famine small scale structure |
|
84:06 | a preferred orientation. So, let's at what we have here. The |
|
84:10 | thing we have is uh layered And you can see that these layers |
|
84:16 | pretty much like layers we saw previously the cliff face. Except it's much |
|
84:21 | scale. In fact, these layers laid down in a glacial situation in |
|
84:26 | lake. And these these are yearly , yearly cycles that you can |
|
84:32 | And it's uh it's uh um sample of you can hold this in your |
|
84:40 | . Um here is crystal and you see this crystal looks to be um |
|
84:48 | , doesn't mean you can see right it. But um you know that |
|
84:54 | the inside of this crystal uh is Adams, you probably recognize this crystal |
|
85:02 | calcite. So there are atoms of and carbon and oxygen arranged in a |
|
85:09 | lattice. Uh in little tiny unit which are this shape. And those |
|
85:15 | are all lined up together. And in this case the external shape of |
|
85:21 | crystal is lined up with the internal of all those uh unit cells. |
|
85:31 | here, there's a rock where um . Has a different type of an |
|
85:41 | . Here. You see the layering this is not layering, um uh |
|
85:48 | the force of gravity. This is formed uh response to uh perpendicular to |
|
85:58 | direction of gravity, this is perpendicular a temperature gradient. This is a |
|
86:03 | rock. And it's uh These layers formed uh particular temperature gradient as cool |
|
86:11 | the subsurface. And then later somebody along collected that rock and and uh |
|
86:18 | it into a paperweight. So, the the crash put the external shape |
|
86:24 | it before. Oh, so here's a piece of wood and you |
|
86:32 | even that one has a small scale would preferred orientation. You look carefully |
|
86:38 | this piece of wood, This is out of a tree. And the |
|
86:41 | tree was going like this vertically. so the carpenter this vertically. If |
|
86:47 | look closely here, there's an elongated um cells of the tree uh quite |
|
86:55 | this direction. And so the reason carpenter cuts this way is because it's |
|
87:00 | better for building buildings. If you it in this direction for all the |
|
87:05 | scale structures, appoint advertisement, it the weight of the building better |
|
87:12 | this one looks like a sandstone. can't see any invisible uh huh uh |
|
87:20 | in here. Of course you can there are grades important and probably see |
|
87:24 | with your maybe arc eyeball. But can't see they all look as though |
|
87:32 | oriented randomly. So this rock looks it's analyzing this rock looks like it's |
|
87:37 | traffic but wanted to measure it. um is anti psychotic. The velocities |
|
87:44 | the vertical direction are faster than the across it. So we interpret that |
|
87:50 | um due to small scale cracks in rock. But you can't see with |
|
87:57 | your eyeball and um those are affecting seismic waves or in this case acoustic |
|
88:05 | , ultrasonic waves, uh even though can't see it with your eyeball. |
|
88:09 | so just to prove that we subjected brought to high pressure and anti |
|
88:17 | We went away because the cracks went , I external pressure. And so |
|
88:23 | proved to our satisfaction. The anti in this rock is due not to |
|
88:31 | orientation of the crystals repression for orientation a friend before I leave this |
|
88:40 | let me excuse myself for a You don't think you're seeing me |
|
88:44 | Or maybe you can see me walking from your computer. Now I'm |
|
89:05 | And what I want to do is sharing ST and change your views so |
|
89:15 | you can see me maximum. I am opening up my little magic |
|
89:25 | here and I have in here box magic stuff and included in this magic |
|
89:42 | . Yes, piece of calcite. looks very much like we saw |
|
89:49 | You can see right through it You can see the color of my |
|
89:53 | right through there. But if you closely, you can see that. |
|
89:57 | got got um uh angles, not right angles. You see that that's |
|
90:04 | sharp angle there. And for analyzing kind of crystal, you would obviously |
|
90:09 | to have a coordinate system which is up with the edges of this. |
|
90:14 | wrong. So that you can say as we move in one direction, |
|
90:19 | passing so many unit cells in the direction passing so many unit cells. |
|
90:25 | this rock naturally grows so that the reflect the internal symmetry of of the |
|
90:33 | structure. So starch sharing again back this screen. It's not obeying my |
|
91:01 | I slide directions. What I have do. Yes. Go back here |
|
91:15 | now if I share the screen this , now this is a famous |
|
91:36 | Uh have you all been to the Canyon? This is about a mile |
|
91:41 | the top here of the mesa, here to the bottom and you can |
|
91:46 | lots of zones here where the cliff vertical and then other zones where there's |
|
91:51 | sloping um pile of debris and uh the cliff is reduced to a slope |
|
92:03 | there is a shale. So these well consolidated, uh well cemented sand |
|
92:09 | and behind here is a shale behind , you can see that most of |
|
92:13 | section is shale, it's about a from top to bottom and most of |
|
92:17 | section is shale. When you look at one of those shales, you |
|
92:22 | that it's uh it's on the small is not uniform, it's got uh |
|
92:32 | different grains in it and it's got between the grains and the grains are |
|
92:38 | major sorts. You see these here are more or less round grains like |
|
92:45 | , more or less round grains, call those equity grains and then there's |
|
92:49 | of grains which are shaped like plates they're lying more or less parallel except |
|
92:56 | . They drape over answer, but very obvious that this um uh this |
|
93:04 | rock was uh it's a positive out um quiet waters such that the grains |
|
93:18 | of uh play settled down more or flat and they got to be more |
|
93:24 | more flat as they were buried. so this rock is intrinsically um uh |
|
93:31 | icy topic because of the preferred orientation these clay minerals. It's very clear |
|
93:42 | this way in the core, this is originally up and not this way |
|
93:47 | this way, this way is original to everybody. Remember when we saw |
|
93:53 | picture here and um this picture So I remind you that this kind |
|
94:01 | antisocial that we saw here that is here. So this this even though |
|
94:09 | uh, this is a shale behind weathered slope of um rock pieces and |
|
94:17 | this, this is a loose loose here. You would not want to |
|
94:22 | on here. If you walk down , your feet would slide and you'd |
|
94:26 | off. Uh it's a foot or feet deep of loose rock. And |
|
94:33 | behind here is the shale like we here. Now, in addition to |
|
94:40 | structure, we also have oriented french and this allows me to tell the |
|
94:47 | about how I got personally involved in such. It was the year in |
|
94:55 | before some of you were born And in those days we didn't have |
|
95:00 | the fancy workstations we had today, printed out our setting up sections on |
|
95:08 | . So in 1979 I joined uh and about a week or two after |
|
95:17 | joined chemical in Tulsa, my boss to me and he said leon here's |
|
95:22 | ticket, we're going to Denver in days. So I said what's it |
|
95:29 | ? And he said, well uh exploration office in Denver is considering making |
|
95:36 | bid on some offshore prospects offshore We don't have an office in |
|
95:43 | So the Denver office is handling and all have to understand that in the |
|
95:48 | States the offshore oil and gas is owned by anybody except the US federal |
|
95:54 | that the U. S. Federal does not want to drill for it |
|
95:58 | drill for oil and find it instead want to sell the opportunity to do |
|
96:05 | to oil companies who have the So they have auctions every year and |
|
96:10 | say okay this year we're gonna have auction on these tracks in the in |
|
96:15 | pacific ocean, atlantic ocean and gulf Mexico. And I guess also in |
|
96:21 | in the in the Barents sea and there's an offshore american waters will have |
|
96:30 | auctions and companies are invited to So had been invited to bid on |
|
96:36 | on a prospect offshore California. And exploration team there was very young in |
|
96:43 | days. Uh the whole business was and uh experienced people uh were being |
|
96:52 | away from the major companies like Amoco the smaller companies who offered them more |
|
96:57 | . And so uh large companies did want to match the pay scale of |
|
97:06 | smaller companies. So they said to , you know, they they said |
|
97:09 | their departing talent, they said uh with our blessing, we're gonna replace |
|
97:15 | with cheaper people from the universities. so we went out and hired all |
|
97:20 | oil companies went out and hired fresh , people just like uh Miss Del |
|
97:26 | . And uh you had been graduating 1979 you would have five job offers |
|
97:34 | your on your desk right now and and your husband would be thinking about |
|
97:39 | a bigger house. So these are times of course, but I'm telling |
|
97:43 | about those times. And so we out there, my boss and I |
|
97:47 | out there to advise the young exploration in Denver looking at their data with |
|
97:54 | um properties expertise to figure out is anything in this, in this data |
|
98:02 | we could help the exploration team in give them an advantage in the bidding |
|
98:08 | the auction that was coming up in a few months. And of course |
|
98:12 | was not an expert, I had been hired and why why was I |
|
98:16 | ? It was because we were losing many experienced people and they were willing |
|
98:21 | hire a person like me at the with no real world experience at |
|
98:27 | They were willing to hire me and uh probably wouldn't do that anymore because |
|
98:33 | didn't have any of the specific skills you people have. You two young |
|
98:39 | today have more skills relevant to exploration I did in 79. They hired |
|
98:45 | anyway because um they needed bodies and was willing. And so my boss |
|
98:53 | me out there and we were greeted the exploration team and they rolled out |
|
98:58 | on a large flat table. They out um a paper plot which showed |
|
99:04 | the image of the uh data offshore . And it looked like this except |
|
99:11 | was a flat sheet of paper. seismic data on here and is oriented |
|
99:16 | to west. And so it was duty era. And so just imagine |
|
99:20 | image here and it would be of the time image and the common midpoint |
|
99:28 | would be in this place. And they took out another image uh which |
|
99:34 | north to south. And but they super pose it like I'm doing here |
|
99:39 | the computer because it was in So what they did was they folded |
|
99:44 | over and then they laid it down so so what we had was a |
|
99:49 | D. Section of the subsurface this east to west and this part north |
|
99:55 | south. And it was joined right at the crossing point of the two |
|
99:59 | . Lines I skipped over that Of course we had some two |
|
100:04 | Lines running this way and some running north and south. And so they |
|
100:09 | us two sections. So and so they pointed out just where on this |
|
100:16 | was the mhm Reservoir possible reservoir looking , stay along in here somewhere. |
|
100:27 | my boss took one swift look at and he pointed right here at the |
|
100:32 | point for the two lines. He , what do you think about |
|
100:36 | And so we all looked at that and on the one section it was |
|
100:40 | bold right um reflection. And on other section perpendicular it was very |
|
100:48 | This was the the image. And the kids on the exploration team said |
|
100:54 | we didn't notice that uh is that ? And my boss said, well |
|
101:01 | don't know it could be. And looked at me and he said, |
|
101:04 | do you think? Well, I probably the most naive person in the |
|
101:08 | . I had only been on the for a week or two. This |
|
101:12 | basically the first seisint section that I ever seen and looked at seriously, |
|
101:17 | I was also the new hire and had to say something um uh |
|
101:22 | So I said, I don't it could be some kind of |
|
101:26 | So my boss said what could cause . And so of course she knew |
|
101:33 | , he knew about shale and I which would lead to a difference in |
|
101:39 | between the vertical and the horizontal And he knew that was caused by |
|
101:44 | preferred orientation of clay particles, just we saw on the previous line. |
|
101:50 | that kind of preferred orientation could not to a difference in azimuth. Like |
|
101:57 | saw here difference in east west direction to the north south direction. And |
|
102:04 | I said, well, maybe oriented . Remember we saw previous flight oriented |
|
102:12 | . And uh, so that could lead to different um seismic propagation velocities |
|
102:22 | as the folks in the restaurant. so he said, do you know |
|
102:27 | about that? And I said but I can figure it out. |
|
102:31 | that was a clever thing for me say. It gave me uh, |
|
102:34 | breathing room. So, uh, uh, spent the afternoon with the |
|
102:42 | team and then we went home even uh, the end of the day |
|
102:46 | the next day. We went And in the next couple of weeks |
|
102:50 | learned a lot about anti socks. I called up the kids on the |
|
102:56 | team back in Denver and I good news, I solved your |
|
103:00 | And they said, which problem was ? So of course they had paid |
|
103:05 | attention at all to us. Pointy folks from the research center. Uh |
|
103:10 | had only invited us because their boss suggested we should, they had checked |
|
103:15 | box. And as soon as we the uh room, probably even before |
|
103:20 | left the building, they had resumed um, conventional analysis, uh, |
|
103:27 | these features that my boss had but it was too bad because those |
|
103:32 | turned out to be important and led uh it led to my building an |
|
103:40 | professional career based on an just from lucky happenstance that days. So let's |
|
103:49 | at some of the things I learned those first two words. So if |
|
103:56 | rocks are anisotropy, we need to with the tensor wave equation. And |
|
104:01 | we still have the hell bolts theorem we still have a scale scale of |
|
104:06 | that uh that looks like this. going to assume for now that the |
|
104:12 | is uniform and so we have three . We respect the space here and |
|
104:19 | is on this side and the scale potential here. So previously we solve |
|
104:25 | problem, assuming that the stiffness sensor the ice. A tropic special |
|
104:32 | Now we have to be more realistic that. So what we wanna do |
|
104:37 | apply this equation to the simplest case elastic anisotropy, which we call polar |
|
104:44 | . It's valid for shales and thin sequences, lot for fractures like we |
|
104:52 | about. But this is um with looking back, I want to discuss |
|
104:59 | situation first and in that case the matrix looks like this, we saw |
|
105:06 | uh before I think the first uh we assume in this case that |
|
105:12 | west is the same as north So these two horizontal directions are a |
|
105:17 | one, but it's different from this and in the same way we have |
|
105:23 | share module I which are the same one which is different. And so |
|
105:27 | makes a total of four independent constants the diagonal here, plus 1/5 1 |
|
105:33 | here, and which is also repeated . And then this one here we |
|
105:39 | from. So this is the simplest of geophysical interest. I'm sorry that |
|
105:49 | went from two constants, you and and near to five. It |
|
105:55 | have been nicer if we had had simpler case to learn from. And |
|
106:01 | fact there is a simpler case, gonna stop sharing here, look at |
|
106:06 | screen and we're gonna hold up another , see this crystal here, anybody |
|
106:15 | what that is. I think you know if I handed it around uh |
|
106:23 | though you're not geologist, you know geology to recognize this is a piece |
|
106:29 | fool's gold and its iron sulfide and happens to form into cubes like |
|
106:38 | So here's a nice cubic sample. this is um this turns out to |
|
106:45 | simpler representation uh the elasticity tensor than one I showed you. But we're |
|
106:56 | gonna we're not gonna discuss it because hope this works. No, |
|
107:08 | doesn't work. You got to uh sharing. Go back to this thing |
|
107:27 | okay, now I'm gonna share and I'm gonna have control of the presentation |
|
107:52 | this works. So here are five parameters. And we're gonna uh here's |
|
108:01 | the system that we resume. And the QB case that I showed had |
|
108:07 | independent uh three independent parameters instead of . Uh more complicated than I |
|
108:17 | which has just two but less complicated this one with five. But we |
|
108:23 | we don't want to discuss the cubic in geophysics because there are no features |
|
108:29 | the earth larger than the one I showed you where uh which have cubic |
|
108:35 | . So um this is the simplest . Now we know that this quantity |
|
108:45 | governs vertical pre way propagation and this governs horizontal. This is the |
|
108:54 | And then we have to share Marjolein uh fifth parameter which is like a |
|
109:01 | asse. And then um this one calculated so we have two different um |
|
109:07 | diagonal components and four uh different importance this time. Is that on, |
|
109:19 | that again? Okay, so thanks that question. Uh Mr Love a |
|
109:31 | love back in the 19 twenties introduced notation for this kind of anti |
|
109:41 | He called it G. T. . Which stands for vertical transverse |
|
109:45 | So it's vertical because the polar axis vertical. You call it trans firstly |
|
109:51 | should topic because these two transverse directions equivalent meaning these two are equal. |
|
109:58 | why these two are equal. That's very confusing name because it's a type |
|
110:05 | anisotropy. And right there in the of that type of anisotropy is the |
|
110:10 | ice, a trippy. So a name is polar anisotropy because that's that |
|
110:17 | what it is. It's anisotropy with poll of symmetry, which is this |
|
110:22 | . And because this is a polar , all of these transverse direction. |
|
110:27 | that's a better name. That's the name for VTR. And so you |
|
110:32 | see the term the description V. . I uh in lots of places |
|
110:39 | it's slowly changing towards solar energy even the simplest case the quasi P and |
|
110:49 | essentials are coupled. In other words you do a hell most decomposition into |
|
110:57 | curl free part uh and a divergence part of the display shin those are |
|
111:02 | solution. The girl free. Part the displacement vector field is not a |
|
111:09 | and neither is the divergence free. we need a better mathematical idea than |
|
111:14 | given to us by mr helm So we go back to this full |
|
111:21 | equation of motion and we're gonna guess the plane waves are a solution. |
|
111:26 | then we're going to verify the conditions the wave vector which makes this |
|
111:31 | So here's our guest right here, like we did before. And uh |
|
111:35 | our wave vector and the length of wave vector. We put this into |
|
111:39 | equation of motion and uh in So from uh those driven. He's |
|
111:46 | we have multiplication is with different um friend components over the ones that were |
|
111:58 | . And so this is three equations one. Uh So for each value |
|
112:03 | I so there's three equate iculs 12 three. And for each uh each |
|
112:10 | these three equations there uh different right side. And it's got 27 terms |
|
112:17 | we're summing over em and and and . So 27 terms on this. |
|
112:24 | you see it's pretty complicated. So thing we're gonna do is divide by |
|
112:29 | squared. So here is uh one the K squared and here's one of |
|
112:33 | pieces here. So we're gonna call ratio here the square and we're gonna |
|
112:47 | three different solutions for V depending on stiffness elements and depending on the directions |
|
112:56 | propagation which are given here, see K. J. Is a is |
|
113:01 | component of the wave vector. Is the length of the wave |
|
113:05 | So this gives uh what we call direction co sign, This is |
|
113:10 | which depends upon the direction that K . And here is a different direction |
|
113:16 | cake. So the the unknown in equation is the displacement. Here is |
|
113:22 | eye displacement. And for each of 27 terms here there's a different uh |
|
113:29 | of the of the solution you so mathematicians call this type of in equation |
|
113:40 | I can value equation. Why is ? It's because it's got the the |
|
113:46 | quantity here and here and then what's over is zero and here is a |
|
113:53 | and here is a scalar. So you have a matrix operating on the |
|
113:59 | of unknowns being equal to a scalar that uh same vector component, that's |
|
114:11 | Eigen value inflation. And in matrix away to write that is this component |
|
114:18 | with this patriots here and L called with a Sprinkle here and it's a |
|
114:23 | by 22 by two matrix. And , excuse me, it's it's a |
|
114:32 | by three. Matrix is what I see. Why is that? It's |
|
114:36 | we're summing here over J and So uh some of jan and we |
|
114:46 | uh left over uh the M and eye. And so that that's a |
|
114:53 | by three matrix call it L. uh this is the identity matrix, |
|
114:59 | ? So this is uh Matrix three 3 Matrix whose Diagonal elements are all |
|
115:08 | to one and off diagonal elements. that is the way a mathematician likes |
|
115:16 | look at this expression. So here the definition of the components of the |
|
115:23 | in matrix L. And uh So uh this has two kinds of |
|
115:33 | . The easiest solution is to okay, all components of you are |
|
115:37 | . So that's called the triggers and has a nontrivial solution only when the |
|
115:42 | of this matrix is zero. So up in the uh in the glossary |
|
115:51 | what we mean by as determined. the current is a complicated combination of |
|
115:58 | matrix elements. So when you write out explicitly it's a cubic equation In |
|
116:10 | elements of the matrix and it has solutions. Well I can values, |
|
116:17 | right here we only find nontrivial solutions three special values of blocks of B |
|
116:26 | . And those three are called Eigen and each one has associated with it |
|
116:31 | vector which we call it Eigen vector . And that is the solution for |
|
116:36 | , which comes with each of these values. Um harvey. So in |
|
116:45 | case the Eigen drivers are the squares the velocities and the Eigen vectors are |
|
116:51 | corresponding polarization vectors of the displacement, of the case but of the use |
|
117:00 | , give the direction of propagation of way and uh polarization vectors give the |
|
117:10 | of the displacement within that. When that's uh we're gonna solve that equation |
|
117:22 | the special case of pull around. start to me directly but before we |
|
117:26 | to that, let me ask you Miss del rio, uh we have |
|
117:32 | of the above or what I wanna . It's either B or none of |
|
117:39 | above. I'm not sure. Well is definitely true and uh he is |
|
117:49 | true but doesn't answer the question and is also true. That doesn't answer |
|
117:55 | question. Uh So um but B definitely true. I agree with |
|
118:01 | Now Mr will uh let me suppose one to you, A B or |
|
118:07 | or none of the above. So we're getting um um interference uh mr |
|
118:28 | between this course and your other So I'm gonna ask you to mute |
|
118:34 | microphone again and I'll talk our way this. We says here, we |
|
118:39 | to use different mathematics for the anti case because a only valid for tropic |
|
118:47 | field. No, that's not Mr Helm Holtz didn't know anything about |
|
118:50 | , octopi or anti socks or Mr that's a mathematical theory has nothing |
|
118:56 | do with physics. So that's It says that scale of potential is |
|
119:03 | a solution to the equation of Yeah, that uh that uh that |
|
119:16 | also true. The p wave solution we're gonna find here is not gonna |
|
119:22 | from the scale of potential. It's this was also false. And so |
|
119:27 | one is obviously false. So the answer is deep uh meant to you |
|
119:36 | del rio, it says true or . The Eigen value equation is just |
|
119:41 | special case of three simultaneous linear equations three unknowns which are homogeneous since all |
|
119:48 | the terms contain one of the So uh let me a minute go |
|
119:56 | here on my screen. You I you have this screen in front of |
|
120:01 | at the same time. So you the question in front of you, |
|
120:05 | gonna go back here. Mhm. here is uh the Eigen value, |
|
120:17 | and you see it is linear and homogeneous because the unknown is in every |
|
120:23 | , there's no terms over here. The source term no terms over here |
|
120:30 | without the unknown and it's linear. it's complicated with just a linear |
|
120:36 | So I'm gonna say This is a case of three. Again, this |
|
120:43 | true. Right? So now let's the solution in the special case uh |
|
120:51 | case corresponding to polar. And I so here's our special case. So |
|
121:08 | gonna apply this case to the previous what I said was from uh from |
|
121:19 | up against here is here's the equation here's the victory question but here is |
|
121:30 | one cent and this is three right? Three equations and one this |
|
121:34 | one component. This is one equation , but it's cubic. And so |
|
121:39 | gonna depend upon uh um combination of the terms in this uh matrix |
|
121:49 | And so even in the simplest even the simplest thing is too |
|
121:55 | So we have to be more clever that. We we can't just sort |
|
122:01 | uh style of a typical equation by for so let's just make a guess |
|
122:14 | um just like we had in H waves and icy tropic sizing. |
|
122:18 | might be a solution to this problem a shear wave which is polarized out |
|
122:25 | the plane of the figure for all of propagation of the shear wave is |
|
122:33 | to be polarized in the horizontal So that's what we're going to look |
|
122:38 | and see if we can find We're gonna look for a similar situation |
|
122:42 | we had with S. H. that is, it's gonna be a |
|
122:45 | which is going to be propagating in X. Three plane of the of |
|
122:49 | screen right here, the X. X. One X three plane is |
|
122:53 | screen. And it's gonna have only line component of polarization. So we're |
|
122:59 | assume that this thing here, which got any one of the uh three |
|
123:08 | any one of the three, I values, we're gonna choose it to |
|
123:14 | an Eigen value corresponding to shear wave . Why isn't she wave propagation? |
|
123:19 | we said right here, it's gonna only polarized, the only non zero |
|
123:25 | quantity in the solution in the Eigen , which corresponds to this Eigen |
|
123:31 | it's in the two directions. So that means is we're gonna have only |
|
123:35 | tool here and we're gonna have uh . Two, that is the component |
|
123:44 | K. In the two directions out the plane. That's gonna be |
|
123:48 | And now let's see if we can this equation and we'll put this, |
|
123:53 | the ice, a tropic expressions for stiffness tips in here, we named |
|
124:01 | particular Eigen value. V. H. By analogy to the icy |
|
124:07 | share wave which is incident upon a , a reflector and with polarization parallel |
|
124:12 | the plane. And so we choose because we're very clever geophysicist. Uh |
|
124:18 | we were ignorant we wouldn't be able do this, but because we're clever |
|
124:23 | going to make this assumption and see it works. So now we're gonna |
|
124:31 | for a solution for uh only non terms R. K. One and |
|
124:36 | three in the in the uh in way of it. So um but |
|
124:45 | uh requirement, we're looking for waves are propagating in the plane of the |
|
124:50 | into the previous equation and all the advantage except for this one for these |
|
124:58 | . Uh we got only K. and K three's appearing here. And |
|
125:05 | see if we have a one actually we have a one here, |
|
125:08 | got to have a one here and have for three here we've got to |
|
125:11 | a three here. That's the way sun works. And the same with |
|
125:14 | these terms, because some of these sensors are zero. Some of these |
|
125:22 | go away. So you're left with these two terms out of the |
|
125:28 | And uh this one has K one . This one has K three squared |
|
125:32 | they have different different elements here. I asked the question about. |
|
125:43 | so okay uh denominator, is it when you if you want to answer |
|
125:55 | me this question, you have to the other um class that you're monitoring |
|
126:01 | that I can hear your voice. cannot silent because I or I can |
|
126:09 | to our writing. Okay, uh do it that way so you can |
|
126:16 | your question, write it down to yourself and we'll hold it and go |
|
126:21 | . Okay? So uh remember that we convert from this four index notation |
|
126:27 | the to index notation, this is 66 and this one is a |
|
126:33 | And uh so that a terms simplify that and yeah, more importantly than |
|
126:49 | , we have only tools here and two here because these terms are gonna |
|
126:57 | unless uh because of this uh stiffness uh the only two terms out of |
|
127:05 | four, which uh excuse me, is not four terms, this is |
|
127:10 | uh it looks like four terms but one of them is a sum over |
|
127:15 | and so when you recognize that most these terms are zero because of the |
|
127:21 | tensor, we come down to only and look at this, this is |
|
127:25 | important. Uh there's only you two the right side here and you two |
|
127:31 | the left side. So bang, did find a solution. Uh our |
|
127:37 | worked and so we can cancel out amplitude youtube for both sides and then |
|
127:46 | find out that the uh the Eigen which we label S. H is |
|
127:53 | to C. 66 times sine squared four times sine square. These are |
|
127:57 | directions of the propagation, you in the X three X one X |
|
128:02 | plan and the polarization is always in X. So our our our guest |
|
128:10 | inspired by our experience with ice, trippy with an S. H. |
|
128:15 | incident upon a plainer medium in our . And sure enough at work we |
|
128:23 | in in finding one of those three values. Uh All the three Eigen |
|
128:32 | are gonna be the squares of And so we found here that the |
|
128:38 | labeled S. H. Has a trigonometry, uh dependence on um angles |
|
128:48 | in the uh 13 player. So corresponding Eigen value is like, so |
|
128:55 | it's got yeah values. The Eigen is a porous in the two |
|
129:02 | So that leaves us with the other components which are coupled together like this |
|
129:07 | we have uh we have in this we've got both you ones and |
|
129:13 | but this is a quadratic quadratic And so we formed formed the determiner |
|
129:20 | this uh and that's a quadratic equation simpler to solve. And the determinant |
|
129:26 | that matrix is given by this. so in this two by two |
|
129:32 | the determinant has a fairly simple definition it is the three by three matrix |
|
129:40 | is much more complicated than this, the two by two determinant. And |
|
129:46 | like this, he's enough. And Here in the 2nd row, l |
|
129:58 | has index number three. Oh so it's a two by two |
|
130:03 | but the industries are not one and . The industries are one and |
|
130:07 | Okay, so that's what this So that's a quadratic equation which is |
|
130:13 | to solve. And here are the solutions. And so we're gonna, |
|
130:17 | these are uh Eigen values. The two Eigen values are the squares of |
|
130:25 | and they're gonna correspond to different modes propagation and one is like a |
|
130:31 | Wave and the other one is like S. V. Wave. Remember |
|
130:35 | SV wave we had before and um , a topic size mix. It's |
|
130:42 | shear wave which is impinge ng on in society, it's a shear wave |
|
130:48 | impinge ng on a horizontal interface with transverse um polarization of course. So |
|
130:57 | polarization is lying in the 13 And so it has a component in |
|
131:02 | V. Direction. So we call S. V. So we're gonna |
|
131:06 | the same notation here but this one gonna be uh independent of any |
|
131:14 | This is inside of a uniform polar tropic body. Now for the corresponding |
|
131:21 | tropic case, the velocity of the . D. Wave and the |
|
131:26 | H. Wave are the same but one is going to be different because |
|
131:30 | is uh the anisotropy case and the is pretty, it's a little bit |
|
131:39 | , but not too bad. Uh quantity for D. Is gonna go |
|
131:48 | and d is I think you would this complicated. It's got squares and |
|
131:54 | powers and square roots and involves lots different um elements of the plastic. |
|
132:05 | so this is the reason why nobody paid much attention to anticipate tropic |
|
132:17 | mix and exploration geophysics Until about This equation was discovered 80 years |
|
132:29 | This equation was discovered by the first ever called himself a professor of |
|
132:36 | He was a Polish guy and he teaching in the University of Krakow in |
|
132:42 | . And he, like I he was the first person who ever |
|
132:46 | himself professor of geophysics. Now, course they're a dime a dozen. |
|
132:50 | if he was the first and his specialty was seismic anisotropy by which he |
|
132:57 | this case only polar anisotropy. And derived many important results um A long |
|
133:07 | ago, it's 120 years ago he this equation and many other important results |
|
133:14 | from that, But nobody paid attention the next 80 years or hardly anybody |
|
133:19 | because of the complexity of D people up their hands at this and |
|
133:24 | you can't understand that, it's just complicated. And so um we've got |
|
133:35 | make some sort of simplifying approximations or and you can see that we have |
|
133:42 | be careful with that because look back here, the only difference in these |
|
133:47 | equations is the algebraic sign here and , so this quantity D. Is |
|
133:53 | difference between a P. Wave and S. T. Way. So |
|
133:56 | can't be casual about that. So first idea is to assume that the |
|
134:06 | the P wave assume for P wave as a p wave expands from a |
|
134:13 | source, it has elliptical wave And when you put that assumption into |
|
134:20 | , things do simplify too bad. Earth is not like that. We |
|
134:27 | lots of cases, most cases where not true. And so we need |
|
134:33 | better idea. And so yeah, sign is the only difference and we |
|
134:41 | have the third mount. So uh um remember Miss del Rio a couple |
|
134:48 | days ago, I told you there's different share waves propagating in um anti |
|
134:54 | media. So here's this one and one and then we have this P |
|
134:59 | . So these two share waves are propagate at different velocities. In general |
|
135:06 | here that each of these two in . Uh Anyway, that's what we're |
|
135:13 | interested in. The it's got four elements of the this distance element. |
|
135:20 | got one too three and four. notice right here is the shear wave |
|
135:33 | . Now this is one of the and this is the this model uh |
|
135:42 | vertical p wave propagation as we'll see a moment. Um uh And so |
|
135:49 | the icy tropic case, that's equivalent K plus four thirds new. But |
|
135:54 | is another share model by itself. 4/3 in addition to the C33. |
|
136:01 | this is a puzzlement that we would . This sheer modular in the people |
|
136:06 | following. And then it appears it appears everywhere. So we got |
|
136:13 | to share waves and one P wave the body of a uniform puller anisotropy |
|
136:24 | . Okay, so what we just is three different solutions A P wave |
|
136:30 | to share waves. And so each of them is gonna have a velocity |
|
136:34 | depends upon the angle of propagation. uh first look at this P wave |
|
136:39 | , here is the p wave um vector and here is the p wave |
|
136:47 | vector. I think you can see your screen that this displacement is not |
|
136:53 | in the direction of the propagation is a drafting error. That is what |
|
136:59 | equations say. So this is not true P way, it's not um |
|
137:06 | not a way of whose divergence is . Nonetheless, I have to tell |
|
137:14 | that uh nobody has ever figured out to either measure or make use of |
|
137:21 | little angle in it. So we're call this a p wave, even |
|
137:26 | we should call it quasi people. , now, for the share waste |
|
137:32 | share wave is a true share It's always it's polarized perpendicular to the |
|
137:38 | . That is perpendicular to the population . So that's a true share |
|
137:43 | But this uh SV mode is a share mode. Can you see with |
|
137:50 | eyeball that this polarization vector is not perpendicular to the direction of propagation is |
|
137:59 | from the um polarization direction. It different from the it does lie exactly |
|
138:05 | the plane, what? It's not perpendicular this and this angle is pretty |
|
138:12 | the same as this angle. And we call this a quasi share wave |
|
138:17 | this is a true share wave. so here we have velocities which are |
|
138:25 | to be dependent on this angle of . Um But we're gonna be um |
|
138:32 | huh. There's no asthma total All of these uh angles are only |
|
138:39 | from the polar symmetry axis. So uh uh uh is here Miss del |
|
138:54 | ? It says an ice tropic blocks abc uh no abc or all of |
|
139:00 | above or none of the above. B I didn't, did you |
|
139:09 | Well it's true but how about this ? Uh Don't the velocities all vary |
|
139:15 | angle but I thought it was only off of that um that original angle |
|
139:22 | then for see I thought there was four stiffness is that we consider not |
|
139:27 | . Okay, so let's let's go . So here are the here's the |
|
139:33 | . And of course these things all hurry with angle, there's the angle |
|
139:38 | there. Now let's go back a further all the way back, all |
|
139:44 | way back. All right back. Okay, and here is the uh |
|
139:54 | the matrix for uh that special case polar anisotropy count them up. |
|
140:01 | 3, 5, 5. Okay, never mind. Okay, |
|
140:10 | um So you blew that one? thought that was an easy one. |
|
140:22 | , I got confused because that the second to last slide before this |
|
140:28 | you said there was four. So I guess I got Yeah, so |
|
140:33 | four included in here, but then the fifth one right here. Got |
|
140:37 | . Ok. Yeah, so maybe was a trick question. Okay, |
|
140:44 | now I have a quick question about angle I met mean those during |
|
140:53 | So what does that angle means? see the incident angle? It's the |
|
141:00 | of the wave propagation vector measured from polar symmetry axis. So here I'm |
|
141:07 | the same angle for all three but if you change this angle, |
|
141:11 | going to get a different velocity for one of these and uh what uh |
|
141:19 | is the angular dependence? Well, given ranking as a function of |
|
141:23 | This is the same angle and you it here and you see it |
|
141:28 | see it here. If you want estimate the ankle, how how do |
|
141:36 | estimate before you measure it? so to know what that angle |
|
141:43 | Uh Say you're interested in the angle incidence upon reflecting horizon. So you |
|
141:49 | trace rays through the overburden velocity model to the uh down to the reflector |
|
141:59 | decide how to convert offsets to because we never measure these angles, |
|
142:04 | ? Uh We measure offsets and you've to convert offsets to angles by retracing |
|
142:12 | a velocity model in the overburden. , uh it's very common that you're |
|
142:19 | sure what the velocity model is. you're gonna have errors. And if |
|
142:25 | overlying rocks or anisotropy, it's even complicated than you might, then you |
|
142:32 | have thought before if you have an topic uh velocity model in the |
|
142:39 | And if the rocks are really anti , then your conclusion about the angle |
|
142:44 | incidence is going to be wrong. we'll see a few more words about |
|
142:51 | . Uh and if if you use velocity model to estimate it. So |
|
142:58 | the p wave velocity p waves and waves have the same angle in your |
|
143:06 | well in the real Earth, uh could very well be different. But |
|
143:12 | yeah, in the real ethnic could well be different. But in the |
|
143:15 | that I just showed that was just cartoon and the real Earth, of |
|
143:21 | , uh you can have share waves at any angle and p waves propagating |
|
143:27 | any angle, Sure and not necessarily same. Absolutely not. Now it |
|
143:40 | true that if you had if you a cartoon situation with uniform overburden and |
|
143:48 | horizontal layer and you're interested in reflections a horizontal layer, at depth below |
|
143:55 | uniform or anti psychotropic layer. Uh balance point is gonna be um the |
|
144:03 | between the source and receiver. And can solve that problem with simple |
|
144:08 | Uh Not with great tracing, That is trivial, but the real problem |
|
144:15 | more complicated. You've got to trace and the res are gonna be changing |
|
144:22 | at every layer in the interface in the overburden following Snell's law. And |
|
144:30 | gonna be different for p waves for waves. So when it gets down |
|
144:34 | the reflector, uh it's gonna be different angle for the stairways than for |
|
144:40 | three wives in general. And then it's a one d problem, it |
|
144:44 | uh exactly symmetric as it comes back . Okay, so uh the big |
|
144:54 | that's been made in the past 120 here ever since that first policy of |
|
145:01 | is to recognize that the previous assumption we use to simplify those complicated |
|
145:09 | we assume elliptical p waves and real are not like that. So we |
|
145:17 | see, say with good confidence is anti sox tree they have, it's |
|
145:23 | be a week and that is, know that we found out so much |
|
145:30 | the Earth by ignoring the anti secretary assuming the anisotropy zero, surely the |
|
145:37 | um, step towards a full understanding to assume the anisotropy is weak, |
|
145:44 | zero bit small. So that's what going to consider next. Now, |
|
145:51 | the reason this was the first guy did uh size mechanics, name of |
|
145:58 | Rudzki and he lived a long time . And then much later Klaus, |
|
146:05 | um, made was the first guy that. He really was the first |
|
146:09 | all that time, um, um years difference in their ages and this |
|
146:16 | is dead, but Klaus is still us. So almost 100 years, |
|
146:21 | , a big difference between these two . And so, uh, Klaus |
|
146:26 | a class, was a soldier in german army and worldwide too, and |
|
146:34 | sure he was a terrible soldier because must have been questioning his superiors. |
|
146:40 | , he must have thought he was real pain in the buck, but |
|
146:43 | was a young man, he was into the army and then after |
|
146:47 | after peace came to europe, uh, physics and it was really |
|
146:55 | of the giants of our profession. alive, still intellectually alive, Still |
|
147:00 | after all these years and almost 100 old. Look at that. And |
|
147:07 | , um, he was the next who understood and he understood everything. |
|
147:11 | the problem is he was smarter than . And so he was happy to |
|
147:19 | deal with the exact equations. And the next guy who understood those was |
|
147:26 | Amoco, my DP colleague, joe who's still with us and whom I |
|
147:32 | um last week at the scG, still working for BP and he understands |
|
147:39 | things and there's the list of people understood is very short. It's only |
|
147:45 | people that I know of and not me what what I did was to |
|
147:53 | the appropriate approximation. And so we that electrical anisotropy doesn't work and why |
|
148:03 | ? It's because most rocks don't conform this approximation. So a better approximation |
|
148:09 | that the anti Satrapi is weak in sense. So let's define what we |
|
148:12 | by that and implement that. So if we look carefully at those previous |
|
148:22 | expressions, we can see in there following five combinations. And we're going |
|
148:27 | re parameter ize the problem in these . And since it starts off with |
|
148:33 | different module, I uh five different and settlements, we need five and |
|
148:39 | of them have the physical dimensions of . And so we're gonna call one |
|
148:45 | those V. P zero and the one we're going to call them. |
|
148:49 | then we're gonna if you look carefully can see these combinations, non dimensional |
|
148:56 | . No see uh these have physical of nothing. And so you can |
|
149:02 | that also that they uh measure the shocks me in the icy tropic |
|
149:10 | these two are the same. So thing goes to zero in the case |
|
149:14 | ice, octopi and the same for . And you can convince yourself it's |
|
149:18 | same for this one. So these non dimensional measurements of anisotropy. And |
|
149:24 | we're going to define we can xoxo as the special case of anisotropy where |
|
149:32 | things are all small compared to But first before we get there, |
|
149:37 | rewrite the exact equations with this primary . And then we're gonna make a |
|
149:45 | expansion, assuming that the both small when we do that magic happens suddenly |
|
149:53 | equations become so simple that anybody can . For example, look at the |
|
149:59 | wave here, it's got that VPc showing up here and it's got two |
|
150:04 | measures of anti shocks being there. one that we would expect, but |
|
150:10 | and this is why elliptical anisotropy doesn't because for an ellipse, there's only |
|
150:17 | electricity. And here there are two parameters which described the angular dependence. |
|
150:25 | then here's the 3rd 1 here. then for the sp term, there's |
|
150:30 | combination for us to get here. made the taylor talks and notice here |
|
150:39 | combination that we're gonna give that a and we're gonna call it sigma. |
|
150:45 | it's nothing new. It's just this . There's um there's re independent. |
|
150:54 | and I see traffic parameters And two and I should tropic philosophies. So |
|
151:02 | see how this uh these right here the three equations that we just showed |
|
151:10 | that I've got here signal in Now let's look at vertical incidents, |
|
151:15 | incidents signed data zero. So this goes away. This term goes away |
|
151:20 | only the one. So um uh left with the vertical p. Wave |
|
151:27 | is called Vp zero. So would clever to uh call this parameter |
|
151:33 | P. Zero. A few pages . Okay now let's look at the |
|
151:38 | ways signed eight equals zero. So get V. S. Zero and |
|
151:43 | same for S. H. So two waves travel traveling vertically have the |
|
151:48 | velocity. So for a vertical share way of propagation. Uh they travel |
|
151:57 | . Now let's look at horizontal horizontal got uh signed data equals one. |
|
152:05 | coast data equals zero. So this goes away, this goes to |
|
152:09 | And so we get for the horizontal wave velocity is one plus epsilon. |
|
152:16 | was the vertical falls. Now let's uh click next at V. |
|
152:24 | H. So we got signed eight one. So we got gamma plus |
|
152:30 | times V. S. S. the S. H. Velocity differs |
|
152:35 | uh huh vertically trapped. Shh. of what we call gamble, it's |
|
152:43 | of the three parameters. But now at uh SV way we got |
|
152:50 | V. We got scientific wonder coast equals zero. So this term goes |
|
152:55 | and we're left with only the S. Zero. It's the same |
|
152:59 | we had over here. But in these different. Sure. Let's draw |
|
153:09 | pictures. So here we have a at this point and we have a |
|
153:14 | front that goes out like so and gone down 2000 m after a certain |
|
153:24 | of time. And horizontally it's gone . Why is that? Because horizontal |
|
153:31 | faster than word of them there. horizontal if epsilon is greater than uh |
|
153:41 | positive, this is going to be than this. So it was only |
|
153:48 | travels further. Also shown a circle which is coming out exactly 2000. |
|
153:54 | that's a way front and here's an topic circle just to guide your |
|
154:00 | Okay, now let's this looks like lips, doesn't it? But it's |
|
154:06 | uh before I get there it's the V. P. Zero implied by |
|
154:12 | of these. Now uh the black looks like any lips but it's not |
|
154:20 | me lay on here any lips. using the magic that's provided to me |
|
154:26 | mr Bill gates, I can draw exactly lips here. I selected |
|
154:31 | So it has the same um verges has the same vertical velocity and the |
|
154:38 | horizontal velocity. But in between it's from the ellipse. So it turns |
|
154:46 | that black is not any limps. there's the horizontal velocity and the vertical |
|
154:57 | different but it's not in lips. next thing I'm gonna do is lay |
|
155:02 | here a different ellipse which I call delta ellipse and that's also elliptical and |
|
155:09 | matches here with vertical velocity, but comes out over here and what is |
|
155:18 | ellipse? This is an ellipse with electricity 5%. Which I've done to |
|
155:24 | , the green curve has electricity 15% delta has 5%. Uh you see |
|
155:33 | um uh the wavefront, the black sticks closer to the delta ellipse at |
|
155:43 | for these small angles, it's closer the delta lips than it is to |
|
155:47 | epsilon ellipse. And then eventually it to peel away from the delta lips |
|
155:54 | to end up on the epsilon. so that's the way that the wavefront |
|
156:01 | , they're all together here and it off close to the delta air lips |
|
156:06 | ends up on the lips. So have the right to ask. |
|
156:13 | so what is this velocity here, is different from the vertical velocity by |
|
156:19 | factor one plus delta. But you , no energy has arrived here, |
|
156:24 | energy has come and gone. The is way out here and this ice |
|
156:28 | tropic uh, case here, that's a guide you're on. So, |
|
156:34 | this distance out here is 15% greater this, this is 5% greater and |
|
156:43 | have the right to ask yourself and me so what, what does this |
|
156:48 | represent Now, before we answer that , I want to make two alternative |
|
156:58 | . One here, here's the equation we start off. And one thing |
|
157:02 | gonna do is use trigonometry to I that science squared equals one minus cosine |
|
157:08 | and I also know that cosign squared one minus sine squared. So implement |
|
157:15 | . And uh, that means that but in here one minus science script |
|
157:21 | puts a minus delta times sine of fourth over here. So this combination |
|
157:29 | , we call that, I'm gonna that the name ada prime epsilon minus |
|
157:34 | . And we call that the weak of any electricity because if the |
|
157:39 | if the wavefront were elliptical, This be a zero and would only have |
|
157:45 | science fair term. And so the and electricity comes from the fact that |
|
157:50 | things are not um, the same real walks. So this number is |
|
157:56 | to be a non zero number and gonna call it a to prime. |
|
158:03 | , I'm gonna reserve the term ada a related quantity, We're gonna call |
|
158:10 | a to prime this simply. And I'm gonna reformulate in another way. |
|
158:16 | I'm gonna assume that if we have angles, we're gonna neglect this |
|
158:23 | whether or not this is a zero for small angles, the sign of |
|
158:27 | sign of a small angle is gonna a small number, sine squared is |
|
158:31 | small number and sign of the fourth even a small smaller number. So |
|
158:35 | gonna neglect this turn, regardless of car fishing because the Trigon metric part |
|
158:44 | so small, that's gonna be true small angles. So since it's 4:30 |
|
158:54 | , this is a good place for to uh break. And so uh |
|
159:00 | going to break here for 15 So I'll see you at 4:45 and |
|
159:07 | come back and pick up at this point. I'm gonna stop sharing here |
|
159:14 | I'm gonna stop my video here. . And then go into presentation |
|
159:24 | Okay, so so far we talked an abstract problem of uh what kinds |
|
159:33 | plane wave solutions exist in polar anti media. Now we want to think |
|
159:39 | how these parameters are gonna show up our data. Okay, So uh |
|
159:48 | have basically two kinds of data, kinds of seismic data. We measure |
|
159:55 | times as a function of offset. call that move out and then we |
|
160:01 | amplitudes. So first let's consider arrival . So here is uh the cartoon |
|
160:10 | we're gonna use to analyze this problem the first instance, we've got a |
|
160:16 | problem as we had before, homogeneous , flat layer down here. But |
|
160:22 | it's an issue trump polar anisha And uh we ask where is it |
|
160:29 | to uh what's the move out of um event as the offset increases in |
|
160:40 | first place because it's homogeneous, we that the bounce point right here is |
|
160:46 | the middle. That's a geometrical argument doesn't make much physics at all uh |
|
160:53 | it's homogeneous and because the wave front because the wave type is the same |
|
160:58 | as it is here. We know bounce, The bounce point is gonna |
|
161:02 | right here in the middle. And , we have this hyperbolic new body |
|
161:11 | that we saw before. And in case where the overburden is aisha tropic |
|
161:17 | this simple problem. This is just and it's um uh given by the |
|
161:25 | theorem and in a more complicated Aisa scenario, layers and so on. |
|
161:32 | recognize that it's the first term in taylor expansion and the parameter of this |
|
161:38 | term is called the move out velocity over the move out to listen, |
|
161:44 | the derivative of the square time with to the square of distance. This |
|
161:49 | the small parameter Yeah, evaluated at zero offset and that's one over the |
|
161:57 | out velocity square. And so that's we had for the icy tropic |
|
162:02 | And now all we do is we this same cartoon for the uh and |
|
162:09 | should drop the case and there we that the move out velocity is given |
|
162:15 | this expression vertical velocity times one plus delta anisotropy prem So you remember this |
|
162:28 | that we had before I told you story about uh how I had this |
|
162:35 | concerning layers of um uh icy tropic and asking themselves why isn't the short |
|
162:45 | velocity equal to the vertical velocity? in the short spread instance, all |
|
162:50 | rays Are traveling almost vertically. So could be. So so you would |
|
162:59 | that the move out lost it would v. zero. And we talked |
|
163:04 | this uh a lot in connection with layered antisocial problem. And it's the |
|
163:10 | answer here as as it is even though these rays traveling near vertically |
|
163:19 | traveling with almost a vertical velocity, we measure instead, you know, |
|
163:25 | is reminding of what we did about layer problem. In that case we |
|
163:30 | the issue by saying what we measure uh the horizontal movement. And it's |
|
163:36 | same here for the layer. What measuring is the horizontal move out and |
|
163:42 | differs from the vertical velocity Because of factor the anti ship traffic factor one |
|
163:50 | dealt so in this case it's uh similar to the multi layer anti psychotropic |
|
163:58 | , but in this case the the medium is uniform homogeneous. And |
|
164:08 | now let's um um look at some implications of this simple little formula. |
|
164:23 | the first place we did find hyperbolic spread move out even though the layers |
|
164:30 | psychotropic. So don't get confused about hyperbolic move out and century. If |
|
164:41 | um uh the offsets are short, gonna get hyperbolic move out. Whether |
|
164:48 | the subsurface is Aissa tropic or an tropic whether it's homogeneous or layered or |
|
164:56 | you're gonna get acrobatic move out. the in this case the anti surgery |
|
165:03 | hidden inside the move out velocity. measure this, we don't measure these |
|
165:08 | things separately. So you can do hyperbolic uh move out analysis and come |
|
165:15 | with a move out velocity. It's got inside there some anisotropy because probably |
|
165:22 | overburden is huh? Now, if ignore that and go ahead and calculate |
|
165:31 | time from the depth, you're gonna the wrong answer because the depth requires |
|
165:37 | arrival time, vertical arrival time, , you know, times the vertical |
|
165:42 | which you don't know, you don't this part. All you know is |
|
165:45 | part. So if you ignore the delta and you uh estimating depths using |
|
165:53 | move out velocity and the correct vertical time. You're going to get the |
|
165:57 | depth. We call that a time depth this time. Very common in |
|
166:03 | business. And there's only two. two to uh to possibilities. One |
|
166:11 | screwed up somewhere in your analysis and the more likely uh subsurface is an |
|
166:18 | property not mr trump. Now, an innocent point. The the anti |
|
166:24 | is magnified in the move out because the following argument. Consider the anti |
|
166:30 | philosophy that we just talked about a minutes ago. And let's restrict ourselves |
|
166:35 | short off sense. So hyperbolic move with short offsets and all the rays |
|
166:41 | traveling down and back with velocities following expression because we're gonna ignore the higher |
|
166:47 | expression here with the Science Square. Square, ignore that. And um |
|
166:56 | let's consider a case where the maximum uh maximum offset has a maximum angle |
|
167:03 | 30 degrees, 30 degrees. So sine of 30 degrees is one half |
|
167:09 | the square is 1/4. So let's a case where the Parameter Delta has |
|
167:15 | value 10%. So what that means 10% times 1/4 means all the grades |
|
167:22 | traveling down and up with velocities within of the vertical velocity. But even |
|
167:32 | the move out velocity differs from the velocity by the full 10 in that |
|
167:39 | . The effect of the anisotropy is in the move out. Which is |
|
167:45 | primary observable a viable times as a of move out. That's our primary |
|
167:51 | . And you see the reason that is this formula doesn't have the Science |
|
167:56 | data in there. It's just one delta. So this is not multiplied |
|
168:01 | the small factor which is comes from fair data. It's it's just one |
|
168:05 | delta. So the and gets magnified our primary observable, which is the |
|
168:12 | out philosophy. That's a real bummer that's the primary reason for um uh |
|
168:23 | time to death miss time because neglected this sub sign interpreting without velocity in |
|
168:34 | of vertical velocities without the corresponding delta . Now the problem that we talked |
|
168:41 | so far is unrealistic uniform overburden. let's talk about um layers. So |
|
168:48 | we have 1234 layers. Each one them is laterally homogeneous, but it's |
|
168:53 | psychotropic, polar. Anti psychotropic. so then let's see what do we |
|
168:59 | to move out velocity in this Well we find is equal to the |
|
169:04 | velocity with a correction factor which I've here average value of delta averaging down |
|
169:11 | the layers uh with a subscript M. S. Because there's some |
|
169:16 | some weights inside this uh inside this it's a weighted average and the weights |
|
169:24 | indicating with the subsequent primaries. And you do what dix did and and |
|
169:32 | some interval velocities by looking at how move out velocity varies from this reflected |
|
169:39 | this one. And this one then find interval velocities that look like |
|
169:43 | every one of them has the local vertical velocity. That's what the subscript |
|
169:50 | out here means local vertical velocity times plus delta. This is the delta |
|
169:57 | for this third layer. And similarly the other layers. So you get |
|
170:04 | when you convert from um average an velocities to interval velocities. You don't |
|
170:13 | away from the and you still have anti sex in there for each of |
|
170:18 | layers. So when you if you to use these interval velocities to convert |
|
170:25 | to death, you would still make mistake time, death miss time each |
|
170:32 | of those internal velocities has an interval for that lamb in it. So |
|
170:39 | can't escape the anti sexually by computing velocities. And you can't escape it |
|
170:44 | considering on short offsets. Because we've assumed that uh we've already assumed that |
|
170:54 | velocity expression is taken from the derivative the move out times in the limit |
|
171:05 | small offsets. Now you can measure anti sunscreen. How do you do |
|
171:14 | by comparing the move out velocity with vertical velocity? How do you get |
|
171:19 | ? Well you you run a VSP the well is drilled and the difference |
|
171:24 | these two is due to the uh parameter of an ice onscreen as it |
|
171:32 | your depth. Of course it's gonna different in every life. So uh |
|
171:41 | a plan. Let's look at longer , observe the non hyperbolic move out |
|
171:46 | use that to estimate delta. So sort of a plausible plan. So |
|
171:51 | we do that, we take data this. So this is real data |
|
171:55 | medical data from a long time And it has been flattened with an |
|
172:00 | velocity function at um near offsets. that uh those uh move out velocities |
|
172:10 | been moved from your offset. But can see that for the far |
|
172:14 | We've overcorrected, overcorrected the move out move out used to look curved down |
|
172:21 | and now it's flat out to this and then it curves up so that's |
|
172:27 | . Uh And so um uh we do like what we did before. |
|
172:32 | consider 1/4 order taylor expansion. This really a second order taylor expansion because |
|
172:39 | small quantity being uh uh expanding is squared. So this is the first |
|
172:46 | here is the second order term but can uh norman called a core check |
|
172:52 | expansion because of this form we got new parameter to determine here but as |
|
172:59 | talked about before in the ascii tropic case um This is not a good |
|
173:06 | because at the largest offsets the square time is increasing with the fourth power |
|
173:11 | offset, we want the square of to increase with the second power of |
|
173:16 | . And that happens if we add physically based term here. So that |
|
173:21 | we get to the furthest offsets this here dominates the one. And so |
|
173:26 | have expert behavior in the denominator cancels the excess up here and to the |
|
173:32 | X is up here. And so what expert behavior on right um velocity |
|
173:39 | of the wrong velocity. And we're do that um uh cleverly by uh |
|
173:48 | the proper values for a four and . And when it turns out that |
|
173:55 | we do that uh the a is be proportional to the a. four |
|
174:00 | this um uh proportionality constant. And this is the horizontal velocity and this |
|
174:07 | move out washing. And so um uh this will ensure that the longest |
|
174:18 | the square time is increasing with the wall set with the horizontal philosophy in |
|
174:25 | . That's what we want. Now the case where we have a uniform |
|
174:33 | an extra traffic layer, this simplifies to the following form and you can |
|
174:41 | this, it looks the same except changed notation. So instead of a |
|
174:46 | here we call this -28. I'm go back here. So instead of |
|
174:51 | a four, it's a -280. just a change of location. The |
|
174:58 | thing is down here we have instead a new parameter a to me instead |
|
175:05 | a new parameter a here's our new a we have a to appearing |
|
175:13 | So this is really important. Um you want to implement this expression, |
|
175:19 | have two independent, you have to um find from the data, |
|
175:25 | spread, move out velocity, a parameter and a print. So I |
|
175:31 | this with a colleague years ago and was excited because that's a real challenge |
|
175:38 | a to a processing geophysicist to find each reflector. These three parameters at |
|
175:48 | vertical rival time. Basically not possible do that. But my colleague |
|
175:55 | Amoco uh published this with me a time ago left. Amoco went to |
|
176:00 | colorado school of mines and one of uh I think his very first student |
|
176:08 | up with this approximation here. And is ada in terms of things we've |
|
176:15 | mentioned, it's a to prime divided one plus 28. Remember ada prime |
|
176:20 | just this simple difference here. So processor only has to estimate two parameters |
|
176:29 | move out parameters for every reflected move out velocity and ada parameter. |
|
176:36 | he does that for every vertical So that guy's name was all |
|
176:41 | if you were paying attention how Khalifa on campus at the University of Houston |
|
176:48 | thursday, this is his professor, was my former chemical colleague went to |
|
176:54 | Colorado School of Mines and his first was all curriculum. Now it often |
|
177:02 | that when a new professor comes to , his first student is the best |
|
177:08 | whatever he whatever comes his way and students after that is never as outstanding |
|
177:14 | the first one. Well, Al went on to uh famous career and |
|
177:20 | he's a famous professor back in Saudi . And so he came to Houston |
|
177:27 | as part of his job as professor geophysics in Saudi Arabia. He was |
|
177:32 | the ScG convention two weeks ago then stayed for a couple of weeks and |
|
177:38 | did us the courtesy of business at University of Houston on thursday gave a |
|
177:44 | interesting talk, not on anti sanctuary on machine learning and that was very |
|
177:50 | and I don't believe that you all there along either of you there |
|
177:59 | it was Oh good. Yeah. you agree that was an interesting |
|
178:04 | Yeah, yeah. Was a very guy. And and here's an interesting |
|
178:12 | thing uh of course is uh Saudi is a Russian jew. And you |
|
178:20 | imagine that these two guys might disagree a number of political um issues, |
|
178:28 | they never talk about those issues. only talked about the geophysics together and |
|
178:33 | been good colleagues for all this time over over 25 years by now. |
|
178:43 | uh let's compare with what we did in Chapter four. Uh back in |
|
178:49 | four, we didn't have any anti , but we did have this uh |
|
178:55 | taylor expansion. And remember we had same term then as we're talking about |
|
178:59 | and we had uh this fourth order with the correction factor here and the |
|
179:07 | A was all determined and had all uh determined. But uh we had |
|
179:14 | challenge. Uh um You see this factor does not need to be determined |
|
179:23 | . It comes from uh this factor uh the horizontal velocity and the horizontal |
|
179:32 | is given by the average of the velocities. This average over the |
|
179:37 | So that's all fully specified. And only have to determine this parameter. |
|
179:42 | this one now with this new We don't have to we don't have |
|
179:48 | use any of this machinery down Uh We have only this term, |
|
179:56 | now it's uh wait a second before say that back in the lecture |
|
180:04 | This term came from ray bending and we have an additional two ray |
|
180:09 | We have anisotropy in there. So with the anti surgery included, the |
|
180:17 | move out is simpler than we had . This is what we had |
|
180:20 | And now we see, we don't to determine this thing down here. |
|
180:24 | don't have to calculate it. It directly from this one, so we |
|
180:28 | have to determine these two parameters. uh actually yeah, that's all. |
|
180:40 | here we have the move out loss . This has nothing to do with |
|
180:44 | squared anymore. This is a calculated the layers. This is actually what |
|
180:49 | measure over here. So it's all now. That's assuming homogeneous layer above |
|
180:58 | reflector. That's this is this one in the stations or whatever. But |
|
181:13 | was for only 11 light. And now we um I understand now we |
|
181:23 | that uh as an approximation, we use the same idea where this uh |
|
181:30 | have uh an effective ada which is over all the upper layers. And |
|
181:37 | great thing is it's the same same down here. So now we we |
|
181:41 | to estimate the short spread move out and the ada parameter for every major |
|
181:49 | of the horizon. When we do , there's gonna be uh contributions to |
|
182:02 | empirically determined a to promote, that's one which flattens to gather at far |
|
182:10 | . And this parameter which we determined both re bending and M. |
|
182:16 | Search. And when you apply that can see that flattening works a lot |
|
182:22 | . It's not perfect for all but now it's flat from here, |
|
182:27 | the way out to here. So is another student, our Khalifa home |
|
182:43 | among the authors which at all have is on there. So this is |
|
182:48 | very interesting um Example which they published 22 years ago. And so in |
|
182:58 | first place, uh this is uh an icy topic, wave propagation through |
|
183:06 | complicated model. And it's a two . Model you can see here and |
|
183:10 | you can see assault body here and fault here and so on. And |
|
183:16 | uh it's what we call 2.5 the so that the model is two |
|
183:23 | but the waves propagate out from the is we're gonna have sources and receivers |
|
183:29 | along here. Uh but the waves propagating out in three dimensions. |
|
183:34 | what that implies is that this model be uh in variant uh into the |
|
183:42 | and out of the screen. And course that is not realistic if it's |
|
183:46 | to be complicated like this in cross in the real Earth, you |
|
183:50 | it's going to be complicated in third as well. But leaving that |
|
183:55 | let's consider some modeling for this 2.5 uh model. And so we're gonna |
|
184:04 | we're gonna present the model in four here. So this panel shows in |
|
184:11 | of gray, the vertical p way , piecewise constant. And here it |
|
184:17 | delta piecewise constant and epsilon piecewise and piecewise cuts. Look here, the |
|
184:26 | is a lot simpler than either delta epsilon. So you can bet that |
|
184:32 | they did was they assumed this distribution a dis and probably assume this distribution |
|
184:38 | deltas. And then calculated this And so the numbers here are not |
|
184:45 | up to uh 15% in delta and to 8% in ADA. Okay, |
|
184:54 | now, with this model, we're calculate uh forward modeling of data using |
|
185:06 | reasonable guys offsets and starts location all here. And then we're gonna take |
|
185:13 | data and um um try to make image. The original model, which |
|
185:21 | course, we know what it We know what we're looking for. |
|
185:24 | gonna try to make an image of model uh from the model data with |
|
185:31 | imaging algorithms. Actually, we're gonna the same imaging algorithms but with different |
|
185:37 | . Ation and I want to concentrate this fall right in here. So |
|
185:46 | the results. So there's the fault you see. And so the first |
|
185:52 | you can see is not a very image is it's got artifacts all over |
|
185:58 | . This one was calculated using I , Kirk off migration. Uh and |
|
186:05 | an issue topic migration with the correct of the uh they knew what the |
|
186:12 | values are because they put them into model. And so this is what |
|
186:16 | get um with the best um imaging available at the time, which was |
|
186:25 | up not very good but may be . So that's panel A. In |
|
186:34 | next panel B. They didn't, pretended that they didn't know what are |
|
186:42 | correct values. And they found from data they found the best the |
|
186:47 | M. O. And they assumed that delta was zero. They could |
|
186:53 | this from the data. Short spread out. They could measure ada from |
|
186:57 | data but they didn't know epsilon and separately. So they just assumed delta |
|
187:05 | zero. So um you can see it's not a bad image. But |
|
187:12 | can you see this image? This part right here is too low. |
|
187:16 | should be here. So this red gives uh guide your eye horizontally. |
|
187:23 | this image point should be up So they got the wrong depth Because |
|
187:31 | assume dealt equal zero. And so in those days, that was a |
|
187:37 | assumption we always always assumed that um . The anti start the traffic parameters |
|
187:53 | all zero back in the in the and then going into the late eighties |
|
187:59 | the nineties. We commonly assumed that we don't know any better, let's |
|
188:03 | set Golf equals zero. We can ada from the far offset move |
|
188:09 | measure the N. M. From the Nero set move out. |
|
188:14 | with those fitted parameters, we got pretty good model except it was coming |
|
188:20 | at the wrong depth. So now here in the art. See, |
|
188:28 | go back to the bad old days assume that all the antiseptic apartment uh |
|
188:34 | and you can see that uh the is really bad. It's got artifacts |
|
188:40 | over it. Look at these artifacts . It's just not a good |
|
188:46 | But that is what we did. what we could do basically assuming I |
|
188:52 | with a fitted move out philosophy and the Anasazi zero. So now here |
|
189:01 | the 4th, let's assume that we a wellbore here and so we know |
|
189:09 | vertical velocities in this zone. So can find the true vertical velocities. |
|
189:16 | now we are making an image with two vertical velocities. We're still still |
|
189:23 | them. And I saw parameters or . So this is aisha tropic migration |
|
189:30 | the true vertical velocities and it's a image. Look at all the artifacts |
|
189:36 | . If we're gonna make uh an with only one parameter. We want |
|
189:41 | use the best parameter which we find the data by finding the best |
|
189:45 | Move out velocity. You were ignoring one and we're using instead the true |
|
189:50 | velocities that we got from the So it's a bad image. But |
|
189:55 | here it's appearing at the correct This image point. Is this tied |
|
190:04 | the same amount as we had up ? Because we assume the delta equal |
|
190:10 | . Mhm. We assume that delta zero both here and here. Uh |
|
190:16 | here we've migrated. We migrated with vertical velocities. But that's not the |
|
190:24 | to correct for my for move out this anti psychotic problem for move |
|
190:29 | You have to correct with we have correct the move out with the best |
|
190:35 | animal velocity, not the vertical So that's why this image is so |
|
190:40 | . But even though it's poor, does have the intersection at the |
|
190:47 | So this is a good um set four pictures which shows the effects of |
|
190:54 | different parameter. Ization of the same received data calculated synthetically from a known |
|
191:05 | and all with the same over the imaging algorithm in this case Kerkhoff |
|
191:15 | But you learn more about in your and image your course and image aircraft |
|
191:23 | . Uh We can do better now if we did the same analysis using |
|
191:29 | . T. M. All these would be better but we still have |
|
191:35 | same kind of death miss tie here the same time. Yeah. So |
|
191:47 | to finish up today um let's answer question. So Miss del rio, |
|
191:53 | already stumbled on this once and uh it carefully now and answer the |
|
192:01 | Just read it carefully. Would it b. 5? Oh because it |
|
192:09 | here P velocity. Remember you saw for the p velocity? We only |
|
192:14 | four and furthermore it says weekly. in for a week a p wave |
|
192:22 | we only need three. So this a big improvement that when we um |
|
192:29 | we do the elastic uh solution for waves, we do need four, |
|
192:34 | don't need five, but we do four for the elastic for the exact |
|
192:39 | , but for the week equation uh only need three and and they're not |
|
192:46 | not the C. One ones and C. Three things, there's those |
|
192:50 | that we called? Uh excellent delta gamma. Well now we don't need |
|
192:55 | for the p wave problem, but do need vp zero for the D |
|
193:00 | problem, so we need V P , delta and epsilon. So the |
|
193:06 | answer is that for three. So this is one of those questions where |
|
193:10 | have to uh read it carefully and on all the special cases which is |
|
193:18 | right here and right here. So I don't know for p waves and |
|
193:24 | waves both, we need five for exact problem for p waves only its |
|
193:30 | And several weekend three. Now mr this is for you. uh we |
|
193:40 | a B. C. Or all the above. And so uh logical |
|
193:45 | right answer for this statement. And start affects V. P V N |
|
193:51 | O. And I think the I you miss daria and I start to |
|
194:06 | affects non parabolic move out which of statements describes this anti psychotic effect. |
|
194:12 | we have a B. C. . To know none of the |
|
194:16 | So I know all of the So we've got to have one |
|
194:21 | Um see it says the non hyperbolic depends upon the near offset primer. |
|
194:35 | delta. That's not true that this this affects the hyperbolic term at the |
|
194:40 | . So this one is false. , you pass that one by. |
|
194:46 | So this is true but it's uh also depends upon not only epsilon but |
|
194:55 | delta in the combination that we call so this is the one I'm looking |
|
195:00 | . Yeah. Yeah and so this is wrong because it's involving SV rates |
|
195:08 | people. Okay so um this is good place to stop for today um |
|
195:16 | because this next topic is a big . And so let's take this one |
|
195:24 | at um 1 30 on friday. so I don't have a quiz for |
|
195:30 | this afternoon but I will be expecting each of you on friday. Uh |
|
195:36 | written questions and I know that mr had several questions coming up. So |
|
195:43 | write all those down and we'll address directly on friday afternoon and then uh |
|
195:50 | the end of the day friday I hand out to you um final exam |
|
195:58 | I think we want to meet in at the university of friend. Is |
|
196:03 | okay with everybody? Yeah we'll meet person and I will hand it out |
|
196:09 | you um uh and paper you like on paper or do you like |
|
196:16 | Um um Electronic I prefer it email I I just uploaded on my ipad |
|
196:23 | do it there. Okay. Yeah if it's paper then you got to |
|
196:28 | it and all that. So I say at the end of the day |
|
196:31 | friday I will send you both the exam and uh by by email. |
|
196:41 | it will be uh sort of like we've seen before for the quizzes, |
|
196:47 | it will cover all the topics with emphasis on these last four topics. |
|
196:55 | it will it will count for 50% your grade. So so far you've |
|
197:01 | 25% and 25% so far. So final example uh account for 50% of |
|
197:09 | final grade and presuming you both you'll get whatever badges and belts come |
|
197:15 | that. I don't think I understand system, but anyway we are consistent |
|
197:21 | that because mr Professor Van has uh that way. And so we will |
|
197:31 | all that on friday afternoon at the of the day and the topic that |
|
197:37 | be uh the final exam will be before open book, unlimited time. |
|
197:46 | be uh an approximate um estimated time me to hours. So it'll be |
|
197:55 | than what you've seen before. Uh you will have you can spend as |
|
198:00 | time as you like between friday afternoon the next Wednesday. And um let's |
|
198:10 | . Then you will both hand it to uh MS. W. |
|
198:17 | You will uh hand yours in by to um Mr Wu and mr wu |
|
198:25 | forward it to me before midnight on . And I think in the interim |
|
198:31 | you see me friday, you're gonna your new course directly saturday morning. |
|
198:36 | I correct about that? No there's course on saturday. Okay that's |
|
198:44 | So you're not gonna be distracted by else, You'll have all day saturday |
|
198:48 | day sunday and then um you're working Tuesday Wednesday. So you gonna be |
|
198:57 | focused on that. But you'll have to consult together. And again let |
|
199:03 | encourage you to uh consult together um ask questions of each other and learn |
|
199:13 | each other. And then when you down to take the exam you have |
|
199:18 | your reference materials in front of you have what I've given you and |
|
199:22 | had whatever anything you want. Uh any textbook, any class notes, |
|
199:29 | just no other person helping you will that and finish it back to me |
|
199:36 | uh Wednesday evening before Wednesday evening. then I will um get it back |
|
199:45 | you. I'm gonna be pretty busy those times so there might be a |
|
199:49 | . Well we'll see how quickly I respond Anyway. That's the program. |
|
199:55 | I will see you all again next at 1:30 on campus. Okay? |
|
200:04 | you. So with that I'm gonna sharing |
|